Understanding these waveforms would be greatly simplified if you had labeled the nodes with "speaking" names (F4 key in LTSpice) or at least indicated which node is n002
point taken
not being conductive over the full 180° [360°] doesn't mean this is not a class A amplifier.
Yes it does. By definition a class A amplifier conducts over the full 360°. If it does not conduct over the full 360° it is not class A.
Having the transistor not correctly biased
The device *is* correctly biased for operation as a class B amplifier.
There are no requirement under the definition of 'Class B' that more than one active device needs to be used. From Wiki:
"In a class-B amplifier, the active device conducts for 180 degrees of the cycle. This would cause intolerable distortion if there were only one device, so two devices are usually used, especially at audio frequencies. Each conducts for one half (180°) of the signal cycle, and the device currents are combined so that the load current is continuous.
At radio frequency, if the coupling to the load is via a tuned circuit, a single device operating in class B can be used because the stored energy in the tuned circuit supplies the "missing" half of the waveform. Devices operating in Class B are used in linear amplifiers, so called because the radio frequency output power is proportional to the square of the input excitation voltage. This characteristic prevents distortion of amplitude-modulated or frequency-modulated signals passing through the amplifier. Such amplifiers have an efficiency around 60%."
Now go back and look at my reply's #9 and #12. A single ended class B amp is not useful at audio frequencies, but as an RF amplifier, with a tuned network as the load, it works just fine. The posted circuit is properly biased and operating as a class B RF amplifier.