# 12v to 5v

#### spike47

Aug 11, 2009
17
Hi

I am making a simple voltage regulator using a TS7805 , as per the diagram attached , to light up some led's in a PC Gaming machine I am building , can I fit another spec of capacitor instead of the ones shown :

1x TS7805 5 volt regulator
2x 1uf capacitor
1x power plug (or other connector)
1x 220 ohm resistor
1x Blue LED (I used a diffused one)

I have plenty 16v 22μf capacitors ! , I have seen simular voltage reducers using a TS7805 and using different spec capacitors .

question : how do you work out in that simple circuet what size capacitors to use .

cheers

spike

#### Attachments

• screen shot 12v to 5v.jpg
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Moderator
Sep 5, 2009
14,077

#### Colin Mitchell

Aug 31, 2014
1,416
The minimum is 1,000u per amp.

#### dorke

Jun 20, 2015
2,342
spike,
If all you need is TO light a LED(s) you don't need to step-down the voltage!
Connect the LED directly to 12V with a series resistor(just like you do with 5v).
The resistor value will be different that is all.

For the LED you used above with 220 Ohm Calculate R for 12V:

R=220+7000/i ; i=LED current in mA

for 5ma ---> R=1.6k
for 10ma ---> R=910
for 20ma ---> R=560

Aug 11, 2009
17

#### spike47

Aug 11, 2009
17
spike,
If all you need is TO light a LED(s) you don't need to step-down the voltage!
Connect the LED directly to 12V with a series resistor(just like you do with 5v).
The resistor value will be different that is all.

For the LED you used above with 220 Ohm Calculate R for 12V:

R=220+7000/i ; i=LED current in mA

for 5ma ---> R=1.6k
for 10ma ---> R=910
for 20ma ---> R=560
Hi dorke

the LED in the pic is only to show power is there .

#### spike47

Aug 11, 2009
17
The minimum is 1,000u per amp.
Hi Colin

I have about 12 led's to light inside the PC , I have no idea what there load is to work out what Capacitors I would use , I think I will go for a resister instead of the TS7805 , i was only going that route because I have a spare TS7805 .

spike

#### spike47

Aug 11, 2009
17
spike,
If all you need is TO light a LED(s) you don't need to step-down the voltage!
Connect the LED directly to 12V with a series resistor(just like you do with 5v).
The resistor value will be different that is all.

For the LED you used above with 220 Ohm Calculate R for 12V:

R=220+7000/i ; i=LED current in mA

for 5ma ---> R=1.6k
for 10ma ---> R=910
for 20ma ---> R=560
Hi dorke

I have no idea what amperage the led's draw ! .

#### BobK

Jan 5, 2010
7,682
Hi dorke

I have no idea what amperage the led's draw ! .
Then you have little hope of driving them correctly.

Using the 12V power is actually more efficient than reducing it to 5V because you can put several LEDs in series and reduce the total current you draw.

You need to determine the forward voltage and current that the LEDs are designed to operate at.

Bob

#### davenn

Moderator
Sep 5, 2009
14,077
Hi davenn

12 v feed is from the PC's power supply , as per my first post ! .

that was very unclear as the power source
My answer could have been very different

The minimum is 1,000u per amp.

Colin's comment ONLY applies if you are supplying from an unregulated source

spike,
If all you need is TO light a LED(s) you don't need to step-down the voltage!
Connect the LED directly to 12V with a series resistor(just like you do with 5v).
The resistor value will be different that is all.

if it is indeed a reasonably standard PC supply ??
then his comments are spot on use the 12V rail as he said, or if you want to, just use the existing 5V rail
there no need to have another 5V reg line

Hi dorke
I have no idea what amperage the led's draw ! .

If they are standard 5mm LED's then around 20 -30mA,

Dave

#### dorke

Jun 20, 2015
2,342
Hi dorke

I have no idea what amperage the led's draw ! .

Well you can easily measure it .
Connect like you intended ( 5v, led,resistor).
use a resistor =1k potentiometer in series with 100 ohm.
Get the correct luminescence you need from the led
-important start with the pot. at max value and lower the resistance!

VF==> measure the voltage on the led.
IF ==> measure the voltage on the 100 ohm and calculate the current through it.

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