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can u explain me how you did? i am needing so.I can.
i did 105.6 / 100 = 0.044 A = Iz and then 5.6/220+2.2k= 2.3mA=IL and then already vo=vz namely vo=5.6V is it true ?Since this is a homework problem, first you show us your work. Then we advise.
ak
5.6/100= 56mA so that iz=56mA and then il=2.3mAPut some brackets in your equations to define what should be calculated first. Thus 105.6/100 should read (105.6)/100
44mA is NOT Iz
5.6/(220+2k2)=2.3mA correct
ix=İz+İL56mA is the current through the 100Ω resistor. This goes two ways, some through the zener and some through the series resistors (2.3mA) so what is left to go through the zener?
thank you for helping , by the way, is my response true? if you say it , i am pleasure.The diagram shows Vo=Vz but does not show where the output would be connected.
The meter is to measure the current through the bypass as the resistor is changed.
On second thought it's got to be this one because it ends with a "?". It's reminiscent of how shrinks are depicted when the patient asks ..."Doc, do you think that this has anything to do with my problem"? And the $100.00/Hr shrink (who never offers and opinion) invariably replies with ... "What do you think"?56mA is the current through the 100Ω resistor. This goes two ways, some through the zener and some through the series resistors (2.3mA) so what is left to go through the zener?
Who can solve this question and where is zener diode's resistance ?
I like Afternoon delight!I was hoping for some Turkish delight.