P
Paul Burridge
- Jan 1, 1970
- 0
Hi all,
I've come across this simple circuit on the 'net that illustrates that
Spice can't perform this kind of simulation without a DC path to
ground. The narrative says that in the real world, the two 'bogus'
resistors shown on this diagram wouldn't be necessary. I've not
encountered this before. Has this defect in Spice been corrected since
the article was written??
Here's the circuit:
http://www.burridge8333.fsbusiness.co.uk/spice_quirk.bmp
I've come across this simple circuit on the 'net that illustrates that
Spice can't perform this kind of simulation without a DC path to
ground. The narrative says that in the real world, the two 'bogus'
resistors shown on this diagram wouldn't be necessary. I've not
encountered this before. Has this defect in Spice been corrected since
the article was written??
Here's the circuit:
http://www.burridge8333.fsbusiness.co.uk/spice_quirk.bmp