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Average Voltage

Harald Kapp

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Nov 17, 2011
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These terms look corerct:
V(i)>2V, D1 ON, D2 OFF, V(o)=(V(i)+2)/2
V(i)<-4V, D1 OFF, D2 ON, V(o)=-4V
-4V<=V(i)<=2V, D1 OFF, D2 OFF, V(o)=V(i)

I didn't check the integral, but a quick simulation using ideal diodes gives the same average as you calculated.
 
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