aussiedownunder
- May 28, 2021
- 2
- Joined
- May 28, 2021
- Messages
- 2
Hi guys, I am just an electronics hobbyist so please keep it simple.
I'm working on a room temperature quantum bit design and I'd like some help from people in electronics.
My initial idea is to use an electronically settable potentiometer to set a position, and later read the resultant throughput voltage. The potentiometer would need to be set by a continuous analog signal. Unfortunately I have found they are only available for setting digitally, i.e. in several steps, so not useful here.
A 2nd idea is to emulate the mechanism used in today's working quantum computers. So an electromagnet on a pivot (or using a small motor) could be switched on to rotate up to 180 degrees, its' field position can then alter a nearby FET, the resultant analog voltage FET throughput is the Qbit setting.
So, might the above work to set an analog voltage range? Or is there any known cheap electronic component or system that can be set and read from, as an continuous/analog device.
I will explain more details later if asked, but attempting to keep it short and sweet.
Lloyd
I'm working on a room temperature quantum bit design and I'd like some help from people in electronics.
My initial idea is to use an electronically settable potentiometer to set a position, and later read the resultant throughput voltage. The potentiometer would need to be set by a continuous analog signal. Unfortunately I have found they are only available for setting digitally, i.e. in several steps, so not useful here.
A 2nd idea is to emulate the mechanism used in today's working quantum computers. So an electromagnet on a pivot (or using a small motor) could be switched on to rotate up to 180 degrees, its' field position can then alter a nearby FET, the resultant analog voltage FET throughput is the Qbit setting.
So, might the above work to set an analog voltage range? Or is there any known cheap electronic component or system that can be set and read from, as an continuous/analog device.
I will explain more details later if asked, but attempting to keep it short and sweet.
Lloyd