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Basic electronics

R

Richard Harris

Jan 1, 1970
0
Hi,

Current is directly proportional to Voltage.
E=I

There for I=E, E=9V, I=9A ?

If this is so, how come you can get a 4.8 V battery in 720 mA and in
1200 mA ?

Would this 4.8 battery allow you to connect to a device that required a
4.8A load?

Thanks.
 
A

Andrew Holme

Jan 1, 1970
0
Richard said:
Hi,

Current is directly proportional to Voltage.
E=I

There for I=E, E=9V, I=9A ?

Proportional does not mean equal. Resistance is the constant of
proportionality:

E = IR or I =E/R
If this is so, how come you can get a 4.8 V battery in 720 mA and
in 1200 mA ?

Are you quoting maximum current (mA) or capacity in milliamp-hours (mAh)
there?
Would this 4.8 battery allow you to connect to a device that
required a
4.8A load?

Possibly, yes. What sort of battery is it? Can you post a link to the
spec?

The capacity (= stored charge = current * time) determines how long it will
last.
 
P

Peter Bennett

Jan 1, 1970
0
Hi,

Current is directly proportional to Voltage.
in a resistive circuit.

No - E = I/R
There for I=E, E=9V, I=9A ?

No. The current depends on the resistance, as well as the voltage.
If this is so, how come you can get a 4.8 V battery in 720 mA and in
1200 mA ?

I suspect that your 4.8 V batteries have a _capacity_ of 720 mA-hours
or 1200 mA-hours. That is, they could theoretically deliver 720 mA
(or 1200 mA) for an hour before becoming fully discharged.
Would this 4.8 battery allow you to connect to a device that required a
4.8A load?

Yes - but it won't run it for long.
 
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