Make sure you have:
CD4013 with V+ to pin 14 and 0V to pin 7, with a 0.1 uF decoupling capacitor across those pins
All inputs on both sides grounded to 0V, except D and CLK on one side
CLK connected through the pushbutton to V+ and through a 10k resistor to 0V
Q-bar connected through a 330k resistor to D, and a 0.1 uF capacitor from D to 0V
Monitor the Q or Q-bar output.
That definitely should work.
Firstly, I *think* that will work.
But if it doesn't...
Since you have two flip-flops there, you could use one of them to debounce the switch (generating a clean clock for the latter.)
In that case, you need a spdt push button switch. The common is connected to V+, and the NO and NC are connected to S and R (respectively) of one flipflop. There are 100k resistors to ground from these pins. The D and CLK inputs are tied low. When the button is pressed, you should get a clean transition, likewise when it is released you will get a clean transition. the Q output will be 1 with the button pressed, otherwise 0.
The Q output then goes to the CLK input of the second flipflop, with Q' tied directly to D (and all other inputs grounded) The Q output of the second flipflop will toggle each time the button is pressed.
This relies on the bounce of the SPDT switch firstly bouncing open the NC contact, then bouncing closed the NO contact when pressed. The reverse happens when released.
The total component count is the same, but I use both flipflops which may be an issue.
Kris's idea is a cunning one though...