Wired in series, I assume? That's looking at the same as one 9V. Any particular reason for using multiple batteries over one?
Yes.
9V batteries (the small 216 style) are not capable of delivering 40mA for very long. Their life will be short. Added to this, they are relatively expensive considering you would want to purchase a really good one to give you a reasonable life. On the other hand, AA cells are cheap, and 40mA is not a large current to draw from them. Cheap ones will do fine.
Having said that, indicators are not turned on for too long.
The LEDs are rated at 1200mcd.
OK, perhaps "visible" was not the right word. Try "noticable". Imagine driving up behind a bike during the day. Will you be loking at some odd thing on the back of a bike to warn you that the rider intends to pull out in front of you? Would you notice his arm sticking out just a tad more?
I guess you have a pretty good excuse for not sticking your arm out though. Perhaps you should consider placing the LED arrangement on a vest (it will be closer to where drivers look) as well as wearing reflective arm bands (that will make your indication with whatever movement you have more visible at night). Or maybe consider moving to a place that drives on the left side of the road. That way your left arm will be less of an issue
At night, the LEDs will be far more visible -- However, the arrow shape would need to be clearly visible or (and preferably AND) be sufficiently off centre to make it obvious for someone with relatively poor eyesight to figure out what they mean and to make the direction obvious.
1200mCd is not very bright these days. However beware that the brightness is generally achieved by reducing the half angle. As soon as you are off axis, or diffuse the light, it is far less bright.
I thought it looked wrong. I still have a bit to learn about reading schematics with regards to diodes.
Heh, easy mistake to make. Probably easier to actually wire it up that way by mistake. Bit you should catch it pretty fast
Since I will be using this on a bicycle I will be riding on the road often, I'm trying to make this as visible as possible without using incandescents.
Fair enough.
Assuming 9V on the output, you're talking about 406uA.
Yep, that's about right, it should be enough. Remember that the transistor has a current gain that should be more than 100, so you should see a collector current of around 40mA or more.
If I'm going to need more than 30mA to drive each bank, I'm going to need way more than 406uA. A 45 ohm resistor at 9V will give me 200mA through the transistor if I want to saturate both the transistor and the 3904. I found a 40 LED timer project, but it isn't switched manually like mine is.
I think you misunderstand. The transistor needs only a small base current to switch a much larger collector current. The base resistor can (and should) be much larger to limit the base current to what is required. Otherwise, you will be wasting almost as much power in that base resistor as you are delivering to the LEDs. You could also consider a logic level mosfet as a switch, but a bipolar transistor is fine.
See above link, assumed 1.85V drop on each (measured; calculating for 2V as listed and designed).
You may find that your LED current is significantly higher than the 20mA you specify on the circuit diagram. That's not a huge issue, as it allows some margin for the transistor not being driven to saturation.
I would breadboard it first, and determine what the LED current actually is. It will vary depending on the characteristics of the transistor, you need to allow sufficient base current to turn it on, but not so much that you waste power, and not so little that the LEDs are dim.
Thanks for all the tips, I hope I don't sound to argumentative or protective of my circuit. It's the first one I've actually designed outside of op amps (and that was nearly 10 years ago).
No problems.