BJT Miller Effect

M

Marco Ferra

Jan 1, 1970
0
Hi. I will be brief.

After testing the frequency response of the NPN BC337 in the lab I came
across the Miller effect. The gain at high frequencies dropped -3dB at
40.6 KHz. One of the questions of the report was to calculate the
internal parasitic capacitances C-pi and C-miu but it seems that I'm
only able, using Miller's theorem, to calculate the total CT parasitic
capacitance.

Is there a way, knowing the upper corner frequency, to obtain
mathematically and individullay C-pi and C-miu knowing the gain
K = (Vc / Vb) ? (btw this gain is negative because Vc(ac) < 0)

And is there a way, not to estimate the value of Rin, that I am making
Rin = Vb / Ib, but to know accuratly also the values of Rx and R-pi?

If I'm seeing this (what I think I know) in the wrong way please do tell
me.

Sincere regards, Marco

R

Robert Baer

Jan 1, 1970
0
Marco said:
Hi. I will be brief.

After testing the frequency response of the NPN BC337 in the lab I came
across the Miller effect. The gain at high frequencies dropped -3dB at
40.6 KHz. One of the questions of the report was to calculate the
internal parasitic capacitances C-pi and C-miu but it seems that I'm
only able, using Miller's theorem, to calculate the total CT parasitic
capacitance.

Is there a way, knowing the upper corner frequency, to obtain
mathematically and individullay C-pi and C-miu knowing the gain
K = (Vc / Vb) ? (btw this gain is negative because Vc(ac) < 0)

And is there a way, not to estimate the value of Rin, that I am making
Rin = Vb / Ib, but to know accuratly also the values of Rx and R-pi?

If I'm seeing this (what I think I know) in the wrong way please do tell
me.

Sincere regards, Marco

Rin, if i remember correctly, is beta*re+rbb' (that is little Remitter
and base spreading resistance); and re is a linear function of current
(it has been 30 years but i think 27 ohms at 1mA - correct me if i am
wrong).

M

Marco Ferra

Jan 1, 1970
0
Robert Baer said:
Rin, if i remember correctly, is beta*re+rbb' (that is little Remitter
and base spreading resistance); and re is a linear function of current
(it has been 30 years but i think 27 ohms at 1mA - correct me if i am
wrong).

Yes. You are right. In fact re = VT / IE.

(being VT bjt's thermal voltage = 25 mV so 25m / 1m = 25 ohms).

and prove it mathematically all will be fine.

Marco

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