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bleeders and what I am doing....

tedstruk

Jan 7, 2012
476
Joined
Jan 7, 2012
Messages
476
I found this great resource on setting resistance and adjusting load, but I closed my laptop and lost the resource.
Setting the resistance I understand fully.

10% RULE-
1. SET RESISTANCE where the amperage is 10% of the LOAD
[current bleed]
where I is amps

IBleed =
I =(0.10)(9.1a)=.91ma ( remark from dummystruk "(0.10 is 10% and 9.1a is the load" )

[resistor bleed]
Where E is volts and
Where R is resistance
OHMS LAW-
RBleed = E / I = R
R = 3v / .00091a = 3297

Select a resistor near the RBleed value - R1 = 3300
(dummystruk OK to here)
Then it says to ---

select a resistor to maintain the voltage.

I1 = I2 + ILoad = [.91ma + 9.1ma] = 10ma = .010a

R2(10v-3v) / .010a = 700 ohms

I did it in my head the first time through... everything was great... then I did it again later, and I am missing the 700ohms every time....

What I am doing wrong... I don't know what I2 is...
Is I1 = 9.1ma and I2 = .91ma?
R2 is my new resistance that maintains voltage, 10v-3v is 7/.010a = 700 the New resistor that maintains voltage is R2 = 700ohms

wow it worked! I don't believe it!

I wonder what I was doing wrong!!!

So what this 10% RULE is about is creating a circuit that works under load and does not use up the voltage?
 

(*steve*)

¡sǝpodᴉʇuɐ ǝɥʇ ɹɐǝɥd
Moderator
Jan 21, 2010
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Jan 21, 2010
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25,505
What are you trying to do? I really can't understand what you're up to.
 

AnalogKid

Jun 10, 2015
2,665
Joined
Jun 10, 2015
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2,665
1. I don't see a question in there.
2. Open the browser history (Ctrl-H) to see past websites.

ak
 
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