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#### [email protected]

- Jan 1, 1970

- 0

waves such as RMS Current = I peak / SQRT(2) and I ave = 2 * Ipeak /

PI, I would like to know if anyone can help with this question;

Consider two bridged class B (single supply) amplifiers driving a

load, the load is connected between each amplifiers output. The power

supply is fed through a large inductor into a large reservoir

capacitor.

For the sake of argument lets say the peak output current is 4 Amps.

This makes the average current 4 x 2 / PI Amps, and this is the

[constant] current in the inductor. The ripple current in the

capacitor is the difference between this average current and the

instantaneous current being supplied into the load. I get the RMS

ripple current as 0.31 Ipeak (using a spreadsheet) but am not sure how

to do the maths to get this answer. Can anyone help?