inlineskater
- Jun 15, 2012
- 13
- Joined
- Jun 15, 2012
- Messages
- 13
Question:
To extend the range of a 0-8.4 mA, 46.3 ohm DC ammeter, what size of shunt resistor should be used to obtain a 92 mA range?
Using the following formula:
Ish/Im = Rm/Rsh
Rsh = shunt resistance
Rm = meter resistance
Ish = shunt current
Im = meter current
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Rsh = (46.3 ohms) (8.4 x 10^-3) / 83.6 x 10^-3
= 3.8892 x 10^-1 / 83.6 x 10^-3
= 4.65 ohms
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Could of I calculated this differently. Looking this it seems correct.
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To extend the range of a 0-8.4 mA, 46.3 ohm DC ammeter, what size of shunt resistor should be used to obtain a 92 mA range?
Using the following formula:
Ish/Im = Rm/Rsh
Rsh = shunt resistance
Rm = meter resistance
Ish = shunt current
Im = meter current
------------------------------------------------------------------------------------------------------------------
Rsh = (46.3 ohms) (8.4 x 10^-3) / 83.6 x 10^-3
= 3.8892 x 10^-1 / 83.6 x 10^-3
= 4.65 ohms
------------------------------------------------------------------------------------------------------------------
Could of I calculated this differently. Looking this it seems correct.
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