Again, you cannot measure the real part of impedance with a d.c. ohm
meter! I realize that non of this is sinking in, but just as an
example that everyone else will understand, try measuring the
impedance of a tweeter using a capacitor as a simple high-pass filter.
Your d.c. ohm meter will register an open circuit, just as it would if
attempting to measure the impedance of a 50-ohm impedance 1/4-wave
monopole antenna.
I have already said that previously. The crossover network would add
other elements to the speaker and the measurement would be open
circuit if there was a cap in series.
Really, it's a no-brainer that all the arm waving it the world will
not change.
You really need to go crack a book or two covering a.c. circuits and
impedance to grasp what is being discussed here.
I don't want to hear your put-downs. I want to hear your explanation
on how I "cannot" as you say, make a DC resistance of a speaker that
has no other components connected to it, as I say in the following
paragraph, and which, as you say, 'hasn't sunk in'.
Nonsense. (By the way, I'm not a tech. I have degrees in both physics
and EE.) I'm simply trying to tell you the way that it actually is,
and not how you perceive it to be.
I don't care. And I don't need to be told that the way it actually is
is anything different than how ai perceive it. Stop being
condescending and treat me like an adult.
The impedance of a speaker, be it 3.2-ohm or 8-ohm CANNOT be
determined by on ohm meter reading, since the resistance of the
speaker's voice coil will vary widely with its power handling
capacity. It you measure the resistance of a 100-200 watt dynamic
speaker, the voice coil resistance can be as low as a fraction of an
ohm. With a 5 or 10 watt speaker, it could be as high as 5-6 ohms.
Neither reading tells you anything about the impedance of the speaker.
So you're telling everyone, not just me, that one *cannot* deduce that
if a speaker, by itself, measures 5 or 6 ohms DC resistance, as _you_
say above, that that very same speaker has _at_least_ an impedance of
5 ohms, or more?
I think we would all really like to hear your answer to this, Mr EE.
To measure speaker impedance, you need to employ an impedance bridge,
or at least an audio frequency VTVM used in conjunction with a series
dropping resistor. When the audio voltage drop across the speaker
matches that across the series dropping resistor, you know that the
dropping resistor value is equal to the impedance of the speaker (at a
specific frequency).
The measurement is that simple, but you can't perform it with only a
d.c. ohm meter.
If you need to isolate both the real and imaginary component of
impedance, that's where you will need an impedance bridge to isolate
the components of impedance that are orthogonal to each other.
Sorry guy, it is you that is posting misinformation on the newsgroup.
And what about yourself? Perhaps you've discovered a new physical
property, negative impedance, that will subtract from DC resistance?
[chest thumping and condescending insults about intelligence snipped]
Next stop: The Twilight Zone.
--
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###Got a Question about ELECTRONICS? Check HERE First:###
http://users.pandora.be/educypedia/electronics/databank.htm
My email address is whitelisted. *All* email sent to it
goes directly to the trash unless you add NOSPAM in the
Subject: line with other stuff. alondra101 <at> hotmail.com
Don't be ripped off by the big book dealers. Go to the URL
that will give you a choice and save you money(up to half).
http://www.everybookstore.com You'll be glad you did!
Just when you thought you had all this figured out, the gov't
changed it:
http://physics.nist.gov/cuu/Units/binary.html
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