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capacitor amplifier. (its got diodes)

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dragon

Oct 31, 2022
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Ok, after more trials and tribulations, Ive got the capacitor amp to work.
It works by a sneaky way I get the capacitors to charge at the same time with a serial short which connects the batteries in
series to make it not charge the caps when the sensor is off. (switch off.)

The issue is, the "collector" has to be jogged on and off cause otherwise the caps dont charge, and the system doesnt work unless the collector turns on and off, to give the caps time to charge.

next thing I need to do is replace the batteries with caps and charge them off a single battery. and then theres more issues with getting it to possibly make an oscillator function. And it dont work without diodes.

 

dragon

Oct 31, 2022
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I can make it work with weapons grade bolognium.;)
Where are the blinking LEDs?

The blinking leds are coming up, but theres some more issues, and the thing is going to be the size of a couple of houses, with 1000 diodes in it, but it might get there...
 

kellys_eye

Jun 25, 2010
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So, you haven't learned anything then - despite the efforts of a few decent members who have taken their time to TRY to get you to understand just the basics of electricity?
 

dragon

Oct 31, 2022
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It seems to be working to me, I might be looking at the outputs wrong. ;)
 

Delta Prime

Jul 29, 2020
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Heck , I didn't see any outputs.

Yeah!there's a storm on the loose, sirens in my head
I'm wrapped up in silence, all circuits are dead.
I cannot decode, my whole life spins into a frenzy
Help I'm steppin' into the twilight zone.
 

dragon

Oct 31, 2022
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This one is actually working. But my highvoltage generator doesn't thats all.
 

Delta Prime

Jul 29, 2020
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The term or word "Volts" was named in honor of Alessandro Volta.
And I quote:
You must be ready to give up even the most attractive ideas when experiments show them to be wrong.
-Alessandro Volta.
I admire your tenacity,perhaps you can refocus your "stick to it-ness"
Do you have a breadboard?
 

dragon

Oct 31, 2022
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I admire your tenacity,perhaps you can refocus your "stick to it-ness"
Do you have a breadboard?
I haven't used a breadboard before, when I do a real one I just wire them up in a jangley fashion, it works ok that way, I don't see others doing it, but its another way to. it still soldiers on.
 

Harald Kapp

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I haven't used a breadboard before, when I do a real one I just wire them up in a jangley fashion, it works ok that way,
So far you haven't shown us any real circuit. Only simulations.
Instead of bombarding us with further simulations that most (if not all) of us don't accept as "proof" of anything: Build your first real life circuit. Stop talking about building it, DO it. Then show us results.
 

dragon

Oct 31, 2022
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Last real one I did, I got a x2 amp from a couple of batteries and the sound line output from the computer, but the catch was I needed 2 speakers to do it.

I've nearly got the oscillator to work now!! =) But theres still problems I have to get the solution for, every time I think its going to work, something else goes wrong. But I think i'll definitely get it this year if I'm not dead during it.
 

dragon

Oct 31, 2022
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I can do that too!!! just put an led in place of the speaker.

ur using the speaker as a microphone to do that mr clever?
 

Delta Prime

Jul 29, 2020
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It works by a sneaky way I get the capacitors to charge at the same time with a serial short which connects the batteries in
series to make it not charge the caps when the sensor is off. (switch off.)
Devices like capacitors have an I-V characteristics which contain explicit
dependencies on time.
When the switch is closed, the capacitor voltage cannot change instantaneously.
When switching the capacitor looks like a short circuit. The capacitor voltage must begin at Zero and expotentially increases to "E" volts
Now with that said.
The capacitor current on the other hand instantaneously jumps to E/R.
And exponentially decays to zero.
 

dragon

Oct 31, 2022
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Devices like capacitors have an I-V characteristics which contain explicit
dependencies on time.
When the switch is closed, the capacitor voltage cannot change instantaneously.
When switching the capacitor looks like a short circuit. The capacitor voltage must begin at Zero and expotentially increases to "E" volts
Now with that said.
The capacitor current on the other hand instantaneously jumps to E/R.
And exponentially decays to zero.

Thats one way it happens, The other way is if the capacitor is previously backcharged to the battery before the current is applied to it.
Then it starts off negatively charged, and u can end charging at the ground state if u have a short away diode from it.
So current is always at maximum throughout the whole charging.
 

Martaine2005

May 12, 2015
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Thats one way it happens, The other way is if the capacitor is previously backcharged to the battery before the current is applied to it.
Then it starts off negatively charged, and u can end charging at the ground state if u have a short away diode from it.
So current is always at maximum throughout the whole charging.
Please, please, please try this in the real world with real capacitors.
You may find something interesting happens.
 
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