Yes you are correct, but I think time factor for both the resistances
will remain the same so same amount of current will flow. What do you
think about this?
Since the formula for a capacitor's time constant is T=RC any change
in resistance (R) will change the the time constant. As with any
other circuit, the more resistance the smaller the current. The
smaller the current the longer it can flow at that smaller rate before
the capacitor is discharged. Decreasing the resistance will allow
more current to flow, but, since the capacitor holds a finite amount
of charge, the time over which that greater current will flow before
the capacitor is discharged will be shorter.