Could any one provide me with an easy to understand explanation of how an inducer connected to a capacitor in parallel.
I do not know what an inducer
might be, nor is the quoted sentence an actual question, although it does begin with the interrogative phrase, "Could anyone provide me..."
Electronics is an exact
science and the spelling and meaning of words are critical to understanding. Is it possible that you meant inductor instead of inducer?
Can charge the capacitor if essentially your shorting out the capacitor?
You cannot charge a capacitor that is shorted
. An inductor is not a short
. An inductor has electrical properties of inductance and resistance as well as distributed capacitance among turns of the winding, but it is never a short. Even a short
length of straight wire is never really a short
because it has inductance, resistance, and distributed capacitance from end to end. You might need microwave or greater frequencies to appreciate this. A short
is a connection with insignificant
resistance, capacitance, and inductance. A short
resistance, inductance or capacitance does not exist in the real world, but some things can come close.
Because all the experiments I done when I want to discharge and keep it discharge, I simply short the capacitor?
Well, whatever floats your boat. Or keeps your capacitor safe. I have seen large capacitors rated for high voltages (kilovolts) stored with wire connecting their two terminals, presumably to prevent accidental charging of the capacitor.
Does this have to do with some fancy filtering going on because of the tuned l/c resonating frequency that if charged at the right input frequency the capacitor will not be seen in the resonating circuit as shorted?
Yeah, it's pretty fancy alright. James Clerk Maxwell discovered some fancy equations that pretty much describes what's going on. They turned out to be so useful that the set of four equations were named after him. How's that for receiving rock-star status in all things electrical? In your parallel-connected L/C circuit, at the right frequency the two terminals appear to connected to an open circuit. But they are not. At the right frequency, electrical energy stored in an electrostatic field of the capacitor, and electrical energy stored in a magnetostatic field of the inductor, transfers back and forth between these two components. No components disappear or act shorted as a result. The capacitor does not appear as shorted in the resonating circuit, nor does the inductor. Some energy is lost in resistance and some may be radiated, so at resonance the lost energy must somehow be replaced or the oscillations will decay and vanish.
Hello, Just a silly question as I am learning here.
There are no silly questions, but there may be plenty of silly answers (depending on who you ask). Welcome to Electronics Point @hitsfmdj
. Ask all the questions you want.