Hi wess.vic,
From a quick look at your schematic it looks like you need to swap the collector and emitter resistors. If you do so, now you will get:
Emitter current Ie = (Vbe - 0.7V) / (90 Ohms) ~ 10mA
Collector current will be almost identical to this, so the voltage across the new Rc will be:
10mA * 1kOhm = 10V
With an 18V supply the voltage measured from the collector to ground will be:
18V - 10V = 8V, and the AC voltage gain will be roughly Rc / Re = 1kOhm / 90 Ohms ~ 11
The collector resistor and transistor will get a little warm with the bias current you've chosen, but the circuit should work just fine.
Let us know if it works!