B
billcalley
- Jan 1, 1970
- 0
Hi All,
I have been trying to figure out this basic concept for quite some
time now, but without much success: When purposefully mis-matching an
RF stage (such as a PA) in a 50 ohm system, I sometimes see references
alluding to the fact that the next stage will *not* be able to see 50
ohms due to this mismatched stage. The part that really confuses me
is: Why not? Why can't the PA's output matching network not only
purposefully be designed to conjugately mis-match the PA's output (for
max Pout) AND also present exactly 50 ohms at the other end of this
same matching network? And if, for some reason, this is not
possible, then why not just add another pi (or L) network so as to
give the next stage exactly 50 ohms? Am I understanding this
correctly, or do I have it completely FUBAR'ed up?
Many thanks!
-Bill
I have been trying to figure out this basic concept for quite some
time now, but without much success: When purposefully mis-matching an
RF stage (such as a PA) in a 50 ohm system, I sometimes see references
alluding to the fact that the next stage will *not* be able to see 50
ohms due to this mismatched stage. The part that really confuses me
is: Why not? Why can't the PA's output matching network not only
purposefully be designed to conjugately mis-match the PA's output (for
max Pout) AND also present exactly 50 ohms at the other end of this
same matching network? And if, for some reason, this is not
possible, then why not just add another pi (or L) network so as to
give the next stage exactly 50 ohms? Am I understanding this
correctly, or do I have it completely FUBAR'ed up?
Many thanks!
-Bill