Hi, we have been given exam papers to revise from with no solutions....... yes i know its stupid and means i don't know if what i am doing is right.

ive attached the question and here is my answer

4.46A with a phase angle of 30.38.

but if im doing it wrong i need to know........

my working is as follows:

Vt = 25v to angle of 53 + 33v with no angle

= 58v to angle 53

The magnitude of impedance = 13 (square root of 5 +12 squared)

the angle of impedance = 22.62 degrees. (arctan 5/12)

then i = V/Z

so i get 4.46 < 30.38 A

if any one could confirm that id appreciate it. Thanks, Lee.

ive attached the question and here is my answer

4.46A with a phase angle of 30.38.

but if im doing it wrong i need to know........

my working is as follows:

Vt = 25v to angle of 53 + 33v with no angle

= 58v to angle 53

The magnitude of impedance = 13 (square root of 5 +12 squared)

the angle of impedance = 22.62 degrees. (arctan 5/12)

then i = V/Z

so i get 4.46 < 30.38 A

if any one could confirm that id appreciate it. Thanks, Lee.