Hi, we have been given exam papers to revise from with no solutions....... yes i know its stupid and means i don't know if what i am doing is right.
ive attached the question and here is my answer
4.46A with a phase angle of 30.38.
but if im doing it wrong i need to know........
my working is as follows:
Vt = 25v to angle of 53 + 33v with no angle
= 58v to angle 53
The magnitude of impedance = 13 (square root of 5 +12 squared)
the angle of impedance = 22.62 degrees. (arctan 5/12)
then i = V/Z
so i get 4.46 < 30.38 A
if any one could confirm that id appreciate it. Thanks, Lee.
ive attached the question and here is my answer
4.46A with a phase angle of 30.38.
but if im doing it wrong i need to know........
my working is as follows:
Vt = 25v to angle of 53 + 33v with no angle
= 58v to angle 53
The magnitude of impedance = 13 (square root of 5 +12 squared)
the angle of impedance = 22.62 degrees. (arctan 5/12)
then i = V/Z
so i get 4.46 < 30.38 A
if any one could confirm that id appreciate it. Thanks, Lee.