travispickle
- May 31, 2015
- 2
- Joined
- May 31, 2015
- Messages
- 2
A 22kilaohm resistor is connected in series with a 100nF capacitor under a 5v supply voltage.
Vc = V (1 - e^(-t/T))
The capacitor is fully charged to the supply voltage, use the discharging equation to show the value of the capacitor voltage as a percentage of voltage V after it has discharged for t = T (one time constant?)
What I have done so far:
Vc / V = 1 - e^(-t/T)
Vc = 1 - e^-1 = 1-(1/e)
100 x (1-(1/e)) = 63.2%
Im pretty sure this isnt meeting the questions criteria, as im not including any figures for capacitance, voltage, and resistance, but its the only way I can think to do this? (this is a smaller part of a much larger question)
Do I need to use T=CR somewhere? multiply the capacitance and resistance, and use this figure in place of T to give a different percentage?
Any help would be extremely helpful! thankyou!!
Vc = V (1 - e^(-t/T))
The capacitor is fully charged to the supply voltage, use the discharging equation to show the value of the capacitor voltage as a percentage of voltage V after it has discharged for t = T (one time constant?)
What I have done so far:
Vc / V = 1 - e^(-t/T)
Vc = 1 - e^-1 = 1-(1/e)
100 x (1-(1/e)) = 63.2%
Im pretty sure this isnt meeting the questions criteria, as im not including any figures for capacitance, voltage, and resistance, but its the only way I can think to do this? (this is a smaller part of a much larger question)
Do I need to use T=CR somewhere? multiply the capacitance and resistance, and use this figure in place of T to give a different percentage?
Any help would be extremely helpful! thankyou!!