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Thanks a lot!! but what about the transistor connected to the regulator ?The manufacturer of the voltage/current regulator IC recommends the use of a capacitor in its data sheet for better behavior under input spikes or ripple.
Sorry that wasnt my intention , english is not my native lenguage so expressing myself can be hardSeems you are unappreciative of #2 with your exclamation marks.
You didn't ask originally about the transistor, just the capacitor.
However, the transistor monitors current (RCL) and adjusts the regulator output to suit, depending on set point.( I would imagine)
then it over-charges the battery
Thanks i really appreciate the helpThere are 4 diodes.
The green LED lights if there is input power, or if sufficiently charged batteries are present.
The red LED lights when input power is connected, sufficiently charged batteries are connected, but not if the batteries are shorted.
The diode D1 protects the circuit from power being connected backwards.
The diode D2 protects the base emitter junction of the main pass transistor in the regulator which can be damaged if more than 7 or 8 voltage of batteries are connected to the charger without input power and with C1 discharged.
As you can see, the LEDs don't really indicate anything special.
It's also really odd that it has two forms of current limiting.
It may not. It might under charge them instead.
thanks i'm really new with thisConnect them as shown in the schematic. In series.
What can i add so it detects when the battery is fully charged?When the charging current causes a voltage of more than about 0.7V across the 1.2 ohm resistor (0.7V/1.2 ohm= 583mA) then the transistor turns on and drops the regulator voltage which limits the current.
The horrible circuit does not detect that a battery is fully charged then it over-charges the battery that is bad. Ni-MH battery manufacturers recommend disconnecting the charger when the battery is detected to be fully charged.
What can i add so it detects when the battery is fully charged?