If 60Hz, the 470Ω resistor plus the 5643Ω impedance of the 0.47μF results in 6113Ω total opposition to alternating current.
Calculate as if it was only a 6113Ω resistor in the circuit.
The unmarked capacitor to the right also presents a impedance.
Both in series to power applied at S1 and S2 does the division as if it were resistors.