only 1.3 milliamps? an arduino can output more power than that!!!
I thought it was going to be an amp from what I was doing with it!!! when u have the watts and the load, its very hard to compute what the amps are going to be, because it ends being having to compute a square root and u can only Newton Iterate it, unless u know how to compute the curve!!!!
(is that right?)
So, let me have a go at it. 1 milliwatt, at 600 ohms.
0.001w/ 0.6v = 0.0016. 0.6v/600o = 0.001a
0.001w/ 0.66v = 0.0015 ... oh yeh. 0.77. (thats what u said.)
thats not very loud! but i can hear it through a speaker without an amp!
but funnily, i can put it through less ohms and i get a louder signal, so thats why i thought it was an amp at 1 volt!
so it actually has a resistance to it, I dont understand what kellys_eye is saying when u say its ac coupled. does it involve a capacitor?
so if its only less than 10 milliamps, then i can put pretty heavy resistors on what im doing to keep up with that.
so maybe 20 milliamps is alot louder than what comes out of the headphone jack? (I know its not dc, but it can be dc cancelled with some amount of amp in one direction.)
So thats what I need to do!!!! I have to see if I can not cancel a certain resistance, and then there should be no output from the speaker if im too heavy and the ac cant operate the speaker anymore. (if theres a coupling capacitor.)
I swear its more than a volt tho, because it seems to be able to half work with diodes from my experiments.