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how to find input impedance of bit-per-stage ADC?

J

Jeepster

Jan 1, 1970
0
I've got this Variable Gain Amplifier (AD8369) that I'm using to drive
my ADC (AD9283). The problem is that the Variable Gain Amplifier
requires a load impedance of 1k.

However, I'm not able to find any information from the ADC datasheet
about what the ADC input impedance is.

All I know from the datasheet is that it is a "bit-per-stage pipeline
type converter utilizing switch capacitor techniques."

VGA Datasheet: http://www.analog.com/en/prod/0,2877,AD8369,00.html
ADC Datasheet: http://www.analog.com/en/prod/0,2877,AD9283,00.html

Does anyone know whether the input impedance should be specified in
the datasheet?
If not, how do you find/calculate the input impedance of a bit-per-
stage ADC?

Thanks,
Jim
 
J

Joerg

Jan 1, 1970
0
Jeepster said:
I've got this Variable Gain Amplifier (AD8369) that I'm using to drive
my ADC (AD9283). The problem is that the Variable Gain Amplifier
requires a load impedance of 1k.

However, I'm not able to find any information from the ADC datasheet
about what the ADC input impedance is.

All I know from the datasheet is that it is a "bit-per-stage pipeline
type converter utilizing switch capacitor techniques."

VGA Datasheet: http://www.analog.com/en/prod/0,2877,AD8369,00.html
ADC Datasheet: http://www.analog.com/en/prod/0,2877,AD9283,00.html


Ahm, look under "Analog Input" on page 2. Heck, they even gibe you the
schematic of the analog input in figure 2 on page 5.

Does anyone know whether the input impedance should be specified in
the datasheet?
If not, how do you find/calculate the input impedance of a bit-per-
stage ADC?

It _is_ in the datasheet :)
 
I've got this Variable Gain Amplifier (AD8369) that I'm using to drive
my ADC (AD9283). The problem is that the Variable Gain Amplifier
requires a load impedance of 1k.

However, I'm not able to find any information from the ADC datasheet
about what the ADC input impedance is.

All I know from the datasheet is that it is a "bit-per-stage pipeline
type converter utilizing switch capacitor techniques."

VGA Datasheet:http://www.analog.com/en/prod/0,2877,AD8369,00.html
ADC Datasheet:http://www.analog.com/en/prod/0,2877,AD9283,00.html

Does anyone know whether the input impedance should be specified in
the datasheet?
If not, how do you find/calculate the input impedance of a bit-per-
stage ADC?

Thanks,
Jim

Input Resistance 25°C I 7 10 13 7 10 13 7 10 13 kÙ

Right on page 2.
 
J

john jardine

Jan 1, 1970
0
Jeepster said:
I've got this Variable Gain Amplifier (AD8369) that I'm using to drive
my ADC (AD9283). The problem is that the Variable Gain Amplifier
requires a load impedance of 1k.

However, I'm not able to find any information from the ADC datasheet
about what the ADC input impedance is.

All I know from the datasheet is that it is a "bit-per-stage pipeline
type converter utilizing switch capacitor techniques."

VGA Datasheet: http://www.analog.com/en/prod/0,2877,AD8369,00.html
ADC Datasheet: http://www.analog.com/en/prod/0,2877,AD9283,00.html

Does anyone know whether the input impedance should be specified in
the datasheet?
If not, how do you find/calculate the input impedance of a bit-per-
stage ADC?

Thanks,
Jim

The VGA only "requires" a 1kohm ADC load to terminate that particular
assymetrical, low pass, balanced filter arrangement they show (in the data
sheet) feeding an ADC. The VGA otherwise will run with loads from 0ohms
upwards.
Offhand, that particular filter looks something like Butterworth style
80MHzish, in which case the >1k AD9283 load impedance, will have trivial
effect on the filter rolloff and offers even less signal loss.
 
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