keraynopoylos
- Sep 1, 2012
- 9
- Joined
- Sep 1, 2012
- Messages
- 9
Hi all.
I have this PSU:
http://cnc4you.co.uk/resources/PSU.pdf
So I know the Output(DC) Volts, Amps(max) and Watts(max).
What I'm trying to calculate, is the max current(amps) of the INPUT (AC).
I want to know that so I can properly fuse my mains power cord and also buy a power switch and Estop switch of the appropriate specs.
I would be grateful if the method is briefly explained too, as I'll have to recalculate(after adding a few more loads.
I have found that the formula should be:
Imax = P / Vp x cosφ
Is P the Real power(and if so how to I calculate it?) or the Apparent power(Vdc x Imax = 36 x 11)?
I guess Vp would be the input voltage(AC), 240V?
And how do I calculate the cosφ, when the specs only give me the efficincy(85%)? Is the power factor the same as the efficiency(just not expressed in %), so would it be 0.85?
Thanks in advance.
I have this PSU:
http://cnc4you.co.uk/resources/PSU.pdf
So I know the Output(DC) Volts, Amps(max) and Watts(max).
What I'm trying to calculate, is the max current(amps) of the INPUT (AC).
I want to know that so I can properly fuse my mains power cord and also buy a power switch and Estop switch of the appropriate specs.
I would be grateful if the method is briefly explained too, as I'll have to recalculate(after adding a few more loads.
I have found that the formula should be:
Imax = P / Vp x cosφ
Is P the Real power(and if so how to I calculate it?) or the Apparent power(Vdc x Imax = 36 x 11)?
I guess Vp would be the input voltage(AC), 240V?
And how do I calculate the cosφ, when the specs only give me the efficincy(85%)? Is the power factor the same as the efficiency(just not expressed in %), so would it be 0.85?
Thanks in advance.