#### Integrator741

- Jun 16, 2013

- 125

- Joined
- Jun 16, 2013

- Messages
- 125

I am practising my ability to manipulate units and stuff, and I came across this question that doesn't sound that hard but I just can't get the right answer.

*"The electricity meter on a plant initially reads 6032 kWh. If the plant now runs for 73 minutes at a steady power consumption of 320 kW determine a) Energy consumed in MJ b) The final reading of the meter"*

Answers:. a) 1401.6 MJ; b) 6421.3 kWh

My working out is:

320 kWh/60min = 5.3 kW per min.

5.3 kW per min * 73 min = 386.9 kWh

so the final reading will be 6032 + 386.9 = 6419 kWh

now to convert 386.9 to MJ:

1kWh = 3.6 MJ

386.9/3.6 = 107.472 MJ;

I am close with a) but b)... no idea.

Please help.

Thanks