# Increasing Current

#### Electro132

Feb 12, 2013
261
Hi,

I'm needing help in increasing current from a 1.5 V batt by placing down 3x 100 ohm resistors in parallel circuit with an output. However, i have encountered a problem and found that the resistors (even though they each have their own line) tend to give out about 0.3 A of current each but this is also the same amount for the total output. It is supposed to be 0.9 A but i am getting 1.4 - 1.5 A total current output meaning something is wrong.

Can anyone help?

#### Martaine2005

May 12, 2015
4,963
Hi Electro, that is very confusing to me too.
If the battery is 1.5v and the resistors are 100Ω.
1.5 / 100 = 0.015. How are you getting 0.3A?
And adding all three resistors is 0.045. How are you getting 1.5A?

EDIT: How are you measuring this? What settings on the meter?

Martin

Last edited:

#### Arouse1973

Dec 18, 2013
5,178
Can you show us how you have it connected and are they defiantly 100 Ohm resistors. 1.5 Amps would mean the resistor combination was equalled 1 Ohm. What do you mean it's supposed to be 0.9 Amps?

#### davenn

Moderator
Sep 5, 2009
14,297
Hi,

I'm needing help in increasing current from a 1.5 V batt by placing down 3x 100 ohm resistors in parallel circuit with an output. However, i have encountered a problem and found that the resistors (even though they each have their own line) tend to give out about 0.3 A of current each but this is also the same amount for the total output. It is supposed to be 0.9 A but i am getting 1.4 - 1.5 A total current output meaning something is wrong.

Can anyone help?

Any added resistance is going to DECREASE the current from the battery(s)
There is no way to increase the current above what it is able to supply

show and tell us EXACTLY what you are trying to achieve

#### Electro132

Feb 12, 2013
261
Hi Electro, that is very confusing to me too.
If the battery is 1.5v and the resistors are 100Ω.
1.5 / 100 = 0.015. How are you getting 0.3A?
And adding all three resistors is 0.045. How are you getting 1.5A?

EDIT: How are you measuring this? What settings on the meter?

Martin

I am using a multimeter to measure it. The red probe is in the 10A slot, the black probe in the COM and the switch is placed on 10 A current.

#### Electro132

Feb 12, 2013
261
Can you show us how you have it connected and are they defiantly 100 Ohm resistors. 1.5 Amps would mean the resistor combination was equalled 1 Ohm. What do you mean it's supposed to be 0.9 Amps?

Sorry my fault Adam, i didn't break the circuit and inserted the black and red probes so the current couldn't be read through the multimeter.

#### Electro132

Feb 12, 2013
261
Any added resistance is going to DECREASE the current from the battery(s)
There is no way to increase the current above what it is able to supply

show and tell us EXACTLY what you are trying to achieve

That is not true. Each separate individual line is constantly flowing the same electricity through it therefore it is quite possible to achieve an increase in current by placing each separate individual line in parallel, having the total through a single output. At least that is the idea.

I am trying to achieve learning how to increase current using multiple separate lines which add up to the total output coming through the other end.

#### davenn

Moderator
Sep 5, 2009
14,297
That is not true. Each separate individual line is constantly flowing the same electricity through it therefore it is quite possible to achieve an increase in current by placing each separate individual line in parallel, having the total through a single output. At least that is the idea.

you need to restudy Ohms law.

#### Electro132

Feb 12, 2013
261
Its ok, i've found what i was looking for. Btw, thanks for the study tip Davenn, i don't mind reading up on it some more.

This thread can be closed now.

#### Arouse1973

Dec 18, 2013
5,178
Sorry my fault Adam, i didn't break the circuit and inserted the black and red probes so the current couldn't be read through the multimeter.
No worries, glad you got it sorted.

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