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is this analogy is correct?

M

M.Parker

Jan 1, 1970
0
This post has nothing to do the with different types
of batteries, just for circuit analysis I provided the below link
http://en.wikipedia.org/wiki/Daniell_cell

=> The positive connection of that yellow bulb
instead of connecting it to the copper electrode
if I connect it to the earth, the circuit is closed.

now, would the bulb illuminates or not?
 
H

Helmut Wabnig

Jan 1, 1970
0
This post has nothing to do the with different types
of batteries, just for circuit analysis I provided the below link
http://en.wikipedia.org/wiki/Daniell_cell

=> The positive connection of that yellow bulb
instead of connecting it to the copper electrode
if I connect it to the earth, the circuit is closed.

now, would the bulb illuminates or not?


no.


w.
 
M

M.Parker

Jan 1, 1970
0
Electronworks.co.uk said:
No it won't -

why ?

if you connected it to earth, you need some way of getting the
current to flow back (from earth) to the Zinc electrode.

is it really necessary.?

In your circuit, I guess this is what the salt bridge is doing (enabling the
current to flow back from where it started)

I'm having a nice time, seeing as you asked

why do we need 2 wires to conduct electricity

http://en.wikipedia.org/wiki/Electric_locomotive
http://en.wikipedia.org/wiki/Pantograph_(rail)
I'm afraid that electric locomotives has single wire;
i.e. singlephase
 
M

M.Parker

Jan 1, 1970
0
tadchem said:
Try to trace the path of the electrons. If it doesn't make a closed
loop through the supply, load, etc. then it does not make a circuit.

Tom Davidson
Richmond, VA
Thanks Tom; you are quick and informative.

Small thought Experiment:

A rotating Magnetic field will create a Current in a wire(I said a
single long wire, not 2 pieces, no confusion here)

now, using this current in that single wire,
how to make the bulb illuminates?

If I connect the one end of the wire to the '+' of the bulb
and the '-' of the bulb to the earth.

By default, we are left with the other end of the wire as open.

There is Current in the wire by the effect of the rotating magnetic
field, it would pass through the '+' of the bulb and there by to
Tungsten(or whatever it is) and to '-' side of bulb there by to the
earth.

then, why can't the Bulb illuminates?
==========

Procedure (2)

Instead of 1 single long wire, If I take 2 pieces of wires

One to the '+' of the bulb,
other to the '-' of the bulb

at their both ends, if I joined them now the loop is closed.

If any rotating magnetic field produces the current in the wire
the bulb will illuminates.

but, not in the first case, why?
 
M

M.Parker

Jan 1, 1970
0
Cwatters said:
No the path isn't closed so no the bulb won't illuminate. You would also
have to connect the copper electrode to earth as well.

It is possible to make an "apparently open" circuit work. For example some
touch sensitive switches rely on capacative coupling of the human body to
earth to close the circuit.
My one straight question..,

(q) why the path should be closed to illuminate the bulb?
 
M

Martin Brown

Jan 1, 1970
0
Cwatters said:
No the path isn't closed so no the bulb won't illuminate. You would also
have to connect the copper electrode to earth as well.

It is possible to make an "apparently open" circuit work. For example some
touch sensitive switches rely on capacative coupling of the human body to
earth to close the circuit.

One of the more spectacular examples is with fluorescent tubes under
pylons. Richard Box specialised in impressive dusk displays of this as
artist in residence at Bristol University Physics dept.

http://www.interactivearchitecture.org/richard-box.html

Regards,
Martin Brown
 
J

John KD5YI

Jan 1, 1970
0
M.Parker said:
Thanks Tom; you are quick and informative.

Small thought Experiment:

A rotating Magnetic field will create a Current in a wire(I said a single
long wire, not 2 pieces, no confusion here)


No, the rotating magnetic field will create an electromotive force or
potential (measured in volts) on the wire. The amount of current (measured
in amps) that flows in the wire will be a function of the load placed from
end-to-end on the wire (completing the circuit).


(remainder snipped due to invalid thought experiment assumption)

have a nice time

Thanks. Same to you.

John
 
M

M.Parker

Jan 1, 1970
0
Michael said:
Question - if you connect the copper electrode to earth, and the lamp
to another earth 6 feet away, and the battery is 3VDC, would the lamp
still light?

Thanks,

Michael

Given my 2 hands,

one hand holding the electric wire on the pole and
the other touching the pole.

=> will I feel the electric shock or not ?

I touch only one wire, but not '2' as you people said for the
illuminating of the bulb :-(
 
M

M.Parker

Jan 1, 1970
0
Electronworks.co.uk said:
Are you wearing wellies and is it raining? If so, you might need some
tissues.

Also: 'Do I feel lucky?'

These are questions you need to ask yourself

Still having a nice time - even after all these posts..

Case(a):

If we connect the '+' end of the bulb to the one of the wires of the
electric pole and '-' to the earth, would the bulb illuminates or not?

Case(b):

If we touch the one of the wires of the electric pole with right hand
and the left hand to the Earth, would we feel the electric shock or not?

Both cases are same, but instead of the bulb, if we replace the it with
a human he can feel the shock, but the bulb will not illuminates.

what type of logic is this =-O ?
 
M

M.Parker

Jan 1, 1970
0
Cwatters said:
Lots of ways to answer that.

1) The coper electrode needs to recieve a supply of electrons or the
chemical reaction in the battery stops.

2) The voltage across the bulb causes electrons to flow through it. If the
right hand (+ve) side of the bulb was suddenly made open circuit, electrons
flowing through the bulb would collect there (no place for them to go). This
would reduce the voltage on that side of the bulb. Once the voltage across
the bulb reaches zero no more electrons flow through the bulb.

I will go with the II one; but, I want to hear more reasons
as I'm not completely satisfied :-\ with the above one.

so, at the end the conclusion is

Current is and will always present in "Closed" circuits. But, not in
open.
 
G

greg

Jan 1, 1970
0
M.Parker said:
If I connect the one end of the wire to the '+' of the bulb
and the '-' of the bulb to the earth.

By default, we are left with the other end of the wire as open.

There is Current in the wire by the effect of the rotating magnetic
field,

No, there isn't, at least not a continuous one.

A current will flow for a short time when the wire first
starts to move through the field. But electrons will start
to build up at one end of the circuit, and the resulting
negative charge will tend to stop further electrons from
flowing in. Similarly, the other end of the circuit will
acquire a positive charge due to electrons flowing away
from it, which will tend to attract the electrons back.
Soon an equilibrium is reached, and no more current flows.

If you close the circuit, then electrons can flow all
the way around without building up in any one place, so
a continuous current is possible.
 
G

greg

Jan 1, 1970
0
Michael said:
Question - if you connect the copper electrode to earth, and the lamp
to another earth 6 feet away, and the battery is 3VDC, would the lamp
still light?

Some current will probably flow, because the earth then
forms part of a closed circuit. Whether it's enough to
light the bulb depends on the conductivity of the soil
and the rating of the bulb.
 
G

greg

Jan 1, 1970
0
M.Parker said:
Given my 2 hands,

one hand holding the electric wire on the pole and
the other touching the pole.

=> will I feel the electric shock or not ?

That depends on how conductive the pole is. You
certainly have the potential to feel a shock, because
one side of the mains supply (called the "neutral")
is connected to the earth, and so is the pole.

I strongly recommend that you do NOT try this
experiment!
 
G

greg

Jan 1, 1970
0
M.Parker said:
If we connect the '+' end of the bulb to the one of the wires of the
electric pole and '-' to the earth, would the bulb illuminates or not?

Potentially, yes. If the wire that you touch it to is
the "live" side of the supply, current will flow,
because of the neutral side being connected to earth.
Both cases are same, but instead of the bulb, if we replace the it with
a human he can feel the shock, but the bulb will not illuminates.

If a current flows in one case, it will also flow in the
other case, although the amount of current will be
different, because most light bulbs have a much lower
resistance than a human body does from one hand to the
other.

Whether the current is enough to light the lamp or cause
the human to feel a shock depends on details such as the
conductivity of the pole and the soil.
 
G

greg

Jan 1, 1970
0
M.Parker said:
Current is and will always present in "Closed" circuits.

Not always -- it's possible to have a closed circuit
with no current flowing in it.

What you can say is that it's *possible* for a continuous
DC current to flow in a closed circuit, but not in an
open circuit.
 
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