I have a lead acid (car type) battery charger given to me to repair. I found that it had been subjected to a high load on the output, which cooked the ammeter and permanently open circuited the bi-metal overload protector. I measured the output before this mess, and on the 12volt setting, I am getting about 20 volts, open circuit. I reckon that was the cause of the overload which took the protection out, but I am at a loss as to why the output is so high. The circuit has only a transformer & bridge rectifier and a couple of switches (HI/LO) and a 24 volt output as well. Would a l 12 volt lead acid battery charged at 20v or so become an acid boiler? And would that lead to a low internal resistance in the battery?
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