- Joined
- Nov 17, 2011

- Messages
- 13,084

Start by writing down the truth table for your circuit's function Y=A*B + NOT C.I have no idea how to test my circuit to see if it matches the truth table.

Then check against the truth table Laplace has given you.

Right. That's the gate that goes to 0 when the control input is 0.And is it the And gate?

Now go on to the gate or gates that create the control signal which is 0 when A=B=C=0 ´, and only for this case.

Hint: This gate will have 1 for any other combination of A, B and C, so whenever one or more of A, B or C are 1, the output (the control signal) will be 1, too.

Oh my good, I've almost given away the solution with this hint,.