A
Alan Smithee
- Jan 1, 1970
- 0
Hi,
I'm trying to use this circuit diagram
(http://ourworld.compuserve.com/homepages/Bill_Bowden/page4.htm#whistle.gif)
to control a laser. The circuit runs using +12v, but I'd like to use a
simple +9v square battery. What do I have to consider to drop the voltage?
Can I just drop the resistance? 9 volts is 3/4 of 12. Therefore reduce
resistance by 3/4 - is this right?
My main concern is that the filters will be thrown out and the signal needed
to trigger the flip flop will be too great - I can only whistle so loud.
Also, do I need a relay? The laser I plan to use operates at 3 volts -
could I just add resistance to drop the voltage? or does it not work like
this.
Many thanks
I'm trying to use this circuit diagram
(http://ourworld.compuserve.com/homepages/Bill_Bowden/page4.htm#whistle.gif)
to control a laser. The circuit runs using +12v, but I'd like to use a
simple +9v square battery. What do I have to consider to drop the voltage?
Can I just drop the resistance? 9 volts is 3/4 of 12. Therefore reduce
resistance by 3/4 - is this right?
My main concern is that the filters will be thrown out and the signal needed
to trigger the flip flop will be too great - I can only whistle so loud.
Also, do I need a relay? The laser I plan to use operates at 3 volts -
could I just add resistance to drop the voltage? or does it not work like
this.
Many thanks