I have not put in all the components, but the gain of the opamp is around 15.

Please

**do **provide all components. The circuit as shown will not have a gain of 15. We need to see the complete circuit (at least the part around the opamp) to be able to see what you are actually doing and tell you whether it is correct or not.

When the current is flowing from Point A to Point B the voltage at the micro is greater than 1.65 and less than 3.3V. It is called the positive current?

No. A positive current from A to B will create a positive voltage drop between A (positive) and B. This voltage is fed to the inverting input of the opamp, thus reducing the output voltage, not increasing it

My main question is either the current is positive or negative the flow is from Point A to Point B? How is it possible? For negative current it should flow from Point B to Point A?

It is not clear from your drawing where the current comes from (incomplete schematic). Also as shown by

@Kabelsalat there will be current provided by the output f the opamp via the feedback resistor which will add to the current through the sense resistor. Am I right to assume you want to build a kind of current sensor? Then an inverting opamp is a bad choice for the amplifier due to its low input impedance. Read e.g.

this application note on current sensing for more information.

But I digress from the original question. Whether the current through the sense resistor is positive or negative can be determined from the voltage drop between points A and B. If current flows from A to B and the voltage between A 8+) and B(-) is positive, then the current is positive, too. If the voltage between A nd B is negative, the current is negaitve, too. This is easily explained by Ohm's law:

V = R × I

With R being the (positive) resistance, it follows that the polarity of the voltage equals the polarity of the current. Since you have point B fixed at 1.65 V, you could be able to measure positive currents as well as negative currents, provided you replace the amplifier by an opamp circuit suitable for this design (see the link above or look up "opamp current sensor circuit" on the internet).