here have modified my circuit..please check this
and i know that GBWP=Av * f
this is theoretical explanation
practically how the gain affect the bandwidth of an opamp?
This answer concerns the relation between gain and bandwidth for a non-inverting opamp-based amplifier:
In most cases, we can use a
first order lowpass function for the real frequency dependence of the open-loop gain:
Aol=Ao/[1+s/wo]
Thus, based on the expression for the closed-loop gain (Hfb=Feedback factor)
Acl=Ao/(1+Hfb*Ao) we can write
Acl=1/[(1/Ao)+(s/(wo*Ao*Hfb))].
With 1/Ao<< Hfb and 1/Hfb=(1+R2/R1) we arrive (after suitable re-arranging) at
Acl=(1+R2/R1)[1/(1+s/(wo*Ao*Hfb))]
The expression in brackets again is a
first order lowpass function having the corner frequency
w1=wo*Ao*Hfb.
Hence, due to negative feedback the bandwidth wo (open-loop gain) is
enlarged by the factor Ao*Hfb.
More than that, we can write
wo*Ao=(w1/Hfb)=w1*(1+R2/R1)
This is the classical constant "Gain-Bandwidth" product (GBW=wo*Ao) which can be written also as
w1/wo=Ao/Acl(ideal)
with Acl(ideal)=1+R2/R1.