OT? Weigh your car by checking tire pressure?

[ChairmanOfTheBored]

Once again: I'm not into queers like you are, dimbulb.

You obviously have never understood the remark, dumbfucktard.

It isn't an invitation for sex, dipshit. It is an invitation to ****
off, go **** yourself, you stupid ****.

 

[Gunner Asch]

You obviously have never understood the remark, dumbfucktard.

It isn't an invitation for sex, dipshit. It is an invitation to ****
off, go **** yourself, you stupid ****.

Tsk tsk...more gay trolling then denying it was such. Like that
stupid congress critter with his foot tapping.

Pitiful. Be a mensch...admit you want to be tied over a chair and
reamed by your betters. Else you wouldnt be trolling for a Top.

Gunner

 

[Greg Locock]

I'm tempted to come round and let your tyres down, and watch you try
to catch your now weightless car as it drifts away across the sky...

You, sir, win a prize. That was rather funny.

Cheers

Greg Locock

 

[*]

There are far too many variables involved in getting an accurate
reading in this manner for it to EVER be feasible.

From the book, "THE RACING & HIGH PERFORMANCE TIRE - Using Tires to Tune
for Grip and Balance" by Paul Haney (ISBN 0-9646414-2-9)

Haney is an engineer who works in various racing series including IndyCar.

-----------------------------------------------------

Page 70 -

"Load and Internal Pressure ........If you have a vertical force on a tire,
the pressure inside the tire resists that force by developing a contact
patch of a size so that the internal pressure acting on the ground through
the area of the contact patch equals the load on the tire."

"The contact patch area (A) is equal to the vertical force (Fv) in pounds
divided by the internal pressure (P) in pounds per square inch."

"I'll include these equations which all express this same relationship.
Starting with the last sentence in the previous paragraph:

A (in²) = Fv (lb) / P (lb/in²)

Multiplying both sides of the equation by P and rearranging you get:

Fv (lb) = A (in²) X P (lb/in²)

Dividing each side by A and rearranging you get:

P (lb/in²) = Fv (lb) / A (in²)

 

[Richard Heathfield]

* said:

From the book, "THE RACING & HIGH PERFORMANCE TIRE - Using Tires to Tune
for Grip and Balance" by Paul Haney (ISBN 0-9646414-2-9)

Haney is an engineer who works in various racing series including
IndyCar.

And what would *he* know about it?

<g,d&r>

 

[Anthony Buckland]

....

Think about this: I can over or under inflate my tires easily by a
factor of two (or more) without the wheel's bead hitting bottom. The
vehicle's weight didn't change by a factor of two.

Neither their theories nor their tires hold any air.
...

Ok, now you think about it some more. The pressure of the
tire surfaces against the road isn't uniform as long as the tire
remains effectively round. It's higher near the center of the
footprint, and close to zero at the edge where the tire is
barely touching the road. Deflate the tire, and as the tire
squishes flatter, the pressure becomes more uniform over
an area that hasn't increased a great deal. Deflate the
tire enough, and the wheel has to bring the interior
surfaces of the tire into contact, making the air pressure
suddenly much less significant (the structure of the tire
always supports some weight, just not much relatively
speaking). With inflated tires, just about the only thing
holding the car up is the air pressure (which of course
has to measured while it's holding the car up, and which
of course is strictly uniform inside the tire).

Overinflating by a factor of more than two eventually
leads to the spectacular result I saw in an airline
landing gear tire test. If you're not damaged that much
by flying rubber, you'll now see the car sitting on its rims.
Which will support all its weight. And may need
replacing, along with other structures.

 

[Michael A. Terrell]

Tsk tsk...more gay trolling then denying it was such. Like that
stupid congress critter with his foot tapping.

Pitiful. Be a mensch...admit you want to be tied over a chair and
reamed by your betters. Else you wouldnt be trolling for a Top.

Gunner

He has to troll, what with his big mouth. He scares off everyone who
sees him. He sounds like he's even more desperate than usual.

You should watch them kick "Always Wrong" around on the electronics
groups. They love him on alt.usenet.kooks. They have even given him
several awards for trolling. He was so proud of them, he cross posted
the threads to sci.electronics.design to show them off to everyone like
some really homely girl who finally got an engagement ring.


--
Service to my country? Been there, Done that, and I've got my DD214 to
prove it.
Member of DAV #85.

Michael A. Terrell
Central Florida

 

[Michael A. Terrell]

* said:



And what would *he* know about it?

<g,d&r>

Haney? Wasn't he the guy on Green Acres who invented the gasoline
powered washing machine, built from a 55 gallon drum and an outboard
motor.


--
Service to my country? Been there, Done that, and I've got my DD214 to
prove it.
Member of DAV #85.

Michael A. Terrell
Central Florida

 

[ChairmanOfTheBored]

Tsk tsk...more gay trolling then denying it was such. Like that
stupid congress critter with his foot tapping.

You're a fucking retard.

Pitiful.

Yes, you are, jackass.

Be a mensch

**** off, dumbfuck.

...admit you want to be tied over a chair and
reamed by your betters. Else you wouldnt be trolling for a Top.

Gunner

You seem to know more about the lingo than anyone else here, fucktard.

 

[*]

* said:



And what would *he* know about it?


--

Enough, apparently, for his book to be recognized and sold as an official
publication of the Society of Automotive Engineers (SAE).

 

[ChairmanOfTheBored]

From the book, "THE RACING & HIGH PERFORMANCE TIRE - Using Tires to Tune
for Grip and Balance" by Paul Haney (ISBN 0-9646414-2-9)

Haney is an engineer who works in various racing series including IndyCar.

-----------------------------------------------------

Page 70 -

"Load and Internal Pressure ........If you have a vertical force on a tire,
the pressure inside the tire resists that force by developing a contact
patch of a size so that the internal pressure acting on the ground through
the area of the contact patch equals the load on the tire."

"The contact patch area (A) is equal to the vertical force (Fv) in pounds
divided by the internal pressure (P) in pounds per square inch."

"I'll include these equations which all express this same relationship.
Starting with the last sentence in the previous paragraph:

A (in²) = Fv (lb) / P (lb/in²)

Multiplying both sides of the equation by P and rearranging you get:

Fv (lb) = A (in²) X P (lb/in²)

Dividing each side by A and rearranging you get:

P (lb/in²) = Fv (lb) / A (in²)

It depends on the tire.

It would not be the same on a ten speed bike tire as it would on a
10.00 x 20 truck tire for that same load. Period.

There ARE other variables. The rubber compound is one major one.

A stiffer compound would NOT yield the same patch size as a less firm
one would for the same tire size and inflation pressure. If you cannot
see this is the case, you need to quit looking up relationships you do
not fully understand, and touting the as golden rules.

 

[*]

Tsk tsk...more gay trolling then denying it was such. Like that
stupid congress critter with his foot tapping.

Pitiful. Be a mensch...admit you want to be tied over a chair and
reamed by your betters. Else you wouldnt be trolling for a Top.

Gunner

Obviously, you have hit on the meaning of the word "bored" as used in the
context of "Chair man's" sig.....

...........the "Chair man" of the "bored"......

 

[ChairmanOfTheBored]

You should watch them kick "Always Wrong" around on the electronics
groups. They love him on alt.usenet.kooks. They have even given him
several awards for trolling. He was so proud of them, he cross posted
the threads to sci.electronics.design to show them off to everyone like
some really homely girl who finally got an engagement ring.

You are full of shit, and too goddamned retarded to even know when the
troll kook fucktards in the kootard group make posts that are forged.

I didn't give a goddamn about them or their retarded "awards", you
stupid ****.

 

[Richard Heathfield]

* said:

Richard Heathfield wrote...

Enough, apparently, for his book to be recognized and sold as an official
publication of the Society of Automotive Engineers (SAE).

Would you by any chance be from Germany?

 

[[email protected]]

On Sep 26, 1:47 am, ChairmanOfTheBored .

It would not be the same on a ten speed bike tire as it would on a
10.00 x 20 truck tire for that same load. Period.

There ARE other variables. The rubber compound is one major one.

A stiffer compound would NOT yield the same patch size as a less firm
one would for the same tire size and inflation pressure. If you cannot
see this is the case, you need to quit looking up relationships you do
not fully understand, and touting the as golden rules.

You are talking about second order effects which cause some
inaccuracy. A stiffer compound would have almost no effect.

A ten speed bike tire and a 10.00 by 20 truck tire both loaded to say
50 % of their load rating would be very much the same.

Try measuring the pressure in a car tire, then jack the wheel off the
ground and measure the pressure again. You will be surprised at how
little difference there is in pressure. Post the numbers here so
others can learn.

Dan

 

[*]

You are full of shit, and too goddamned retarded to even know when the
troll kook fucktards in the kootard group make posts that are forged.

I didn't give a goddamn about them or their retarded "awards", you
stupid ****.

Pretty emotional response for someone who doesn't care about what others
say.....

 

[*]

* said:

Would you by any chance be from Germany?

Now, THAT's funny!!!

I'm in North America - some say I'm in Canada, some say I'm in USA........

 

[Michael A. Terrell]

You are full of shit, and too goddamned retarded to even know when the
troll kook fucktards in the kootard group make posts that are forged.

I didn't give a goddamn about them or their retarded "awards", you
stupid ****.

They fake those post because they know that you don't have the guts
to say how you really feel about them. If you didn't hold in your
feelings so much, you could save them a hell of a lot of work.


They love you, no matter how much they 'bore' you.


--
Service to my country? Been there, Done that, and I've got my DD214 to
prove it.
Member of DAV #85.

Michael A. Terrell
Central Florida

 

[E Z Peaces]

If the tire pressures are the same, the contact patch is the same
(approximately), regardless of the tire width.


Typically lower pressures result in higher rolling resistance, due to
increased sidewall flex.

I think tread flexing may matter more than sidewall flexing, and taller
wheels have less of it.

Suppose your tire has a 10" radius and, due to sidewall flexing, the
distance from the center to the pavement is 9". The contact patch
should be 8.7" long, and the tread must flex 26 degrees at the front and
back of the patch.

If you get the same 1" of sidewall flexing on a tire with a 20" radius,
the contact patch will be 13.5" long. A tread 2/3 as wide can carry the
same weight at the same pressure, and it will have to flex only 18
degrees at each end of the contact patch.

My figures are simplified. The tread doesn't seem to grow shorter when
pressed against pavement, so it's not quite the shape of a circle with a
piece sliced off at the bottom.

 

[Rich Grise]

I'm tempted to come round and let your tyres down, and watch you try to
catch your now weightless car as it drifts away across the sky...

That's not entirely true. In fact, the footprint would increase, and
the pressure could never reach zero, unless you used a vacuum pump.
0 PSIG is equal to approx. 14.7 PSIA, you know. ;-)

It certainly wouldn't be very accurate, however. ;-)

Cheers!
Rich