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### Network # Power loss and Energy loss

#### Integrator741

Jun 16, 2013
125
Hello,

I was doing some examples in my electronics book and one showed me how to calculate efficiency of a motor. Output power/Input power. When they found it, they calculated the power loss and energy loss per minute. Can somebody please explain me the difference between "Power loss" and "Energy loss"

Thank you #### (*steve*)

##### ¡sǝpodᴉʇuɐ ǝɥʇ ɹɐǝɥd
Moderator
Jan 21, 2010
25,505
The difference is that one is an amount and the other is a rate.

Power is energy per unit time.

#### Integrator741

Jun 16, 2013
125
The difference is that one is an amount and the other is a rate.

Power is energy per unit time.

"The power loss in the motor is 24.6 - 20.944 = 3.656 kW and energy loss per minute = 3.656*60 = 219.36 kW s"

So the amount of lost power is 3.656 kW and my rate of loosing the power is 219.36 kW per sec?

Does that mean I loose 219.36 kW every second when i use that motor? Or I misunderstand something?

#### BobK

Jan 5, 2010
7,682
Watts is a measure of power. Which is energy per second. You do not lose Killowatts every second, you lose KiloJoules every second. If you are losing power at a rate of 1W then you are losing 1 Joule of energy every second.

Bob

#### KrisBlueNZ

##### Sadly passed away in 2015
Nov 28, 2011
8,393
Power (watts) is a measure of the rate of energy flow. When you turn on a 60W light bulb, it converts energy from electrical energy to light and heat at a rate of 60 joules per second. Every second that the light bulb is turned on, 60 joules of energy is converted from one form to the other. So the wattage tells you how quickly energy is converted; it measures the rate of energy flow.

I'll try a few examples.

A 1 kW electric heater converts electical energy into heat energy (and a bit of light) at a rate of 1000 joules per second. If you run it for one hour (which is 3600 seconds), you have used 1 kWh (one kilowatt-hour) of energy, which is 3,600,000 joules, or 3600 kJ (kilojoules). Here where I live, 1 kWh (3600 kJ) of electrical energy costs about 25 cents.

So a 1 kW electric heater costs 20 cents per hour to run; it uses energy at a rate of 3600 kJ per hour.

If you have a 100W motor that's 90% efficient, that means it consumes 100 joules of energy for every second that it runs, and converts 90 of those joules into mechanical energy. The remaining 10 joules that it consumes every second are converted into other forms of energy - heat, mainly, and vibration/sound. So it is wasting 10 joules per second (10 watts) of energy.

#### Integrator741

Jun 16, 2013
125
Power (watts) is a measure of the rate of energy flow. When you turn on a 60W light bulb, it converts energy from electrical energy to light and heat at a rate of 60 joules per second. Every second that the light bulb is turned on, 60 joules of energy is converted from one form to the other. So the wattage tells you how quickly energy is converted; it measures the rate of energy flow.

I'll try a few examples.

A 1 kW electric heater converts electical energy into heat energy (and a bit of light) at a rate of 1000 joules per second. If you run it for one hour (which is 3600 seconds), you have used 1 kWh (one kilowatt-hour) of energy, which is 3,600,000 joules, or 3600 kJ (kilojoules). Here where I live, 1 kWh (3600 kJ) of electrical energy costs about 25 cents.

So a 1 kW electric heater costs 20 cents per hour to run; it uses energy at a rate of 3600 kJ per hour.

If you have a 100W motor that's 90% efficient, that means it consumes 100 joules of energy for every second that it runs, and converts 90 of those joules into mechanical energy. The remaining 10 joules that it consumes every second are converted into other forms of energy - heat, mainly, and vibration/sound. So it is wasting 10 joules per second (10 watts) of energy.

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