Samuel said:
Typo - should read "1 mF" or "1000 uF"...
The filter will sit right after the rectifier and in front of the
regulator (IC & ext. transistors). Goal of the CLC-filter would be
lowest ripple for C=1 mF.
Samuel
I have not seen a linear regulator that likes to be fed with an
inductance, so I think your choices are CLC or LC or C. The first and
last (capacitive input) tend to charge the caps up to the peak voltage
of the rectified AC somewhere approaching 1.4 times the AC voltage of
the secondary, while the LC (inductor input) tends to average the
rectifier output. This averaging effect only takes place if the
inductor current is continuous throughout the rectification cycle. So
for light loads or insufficient inductance, the voltage will rise.
Indictor input filters are good if the transformer voltage is a bit
too high, and they also spread the diode conduction time throughout
the cycle, lowering the transformer copper losses, line harmonics and
diode peak current. The CLC (pi) filter) doesn't put much AC voltage
across the inductor, so can work with smaller inductance. You just
want ot avoid having a resonance at any rectified line harmonics, so
the fundamental resonance should be lower than the second line
harmonic (the fundamental of the rectified line). But in all cases,
more inductance implies lower ripple, so your design goal of minimum
ripple still implies infinite inductance. By the way, what is the
load that you are so worried about rectifier filtration, if you have a
linear regulator? after the filter? The output ripple will be
dependent on both the filter and the regulator, assuming the filter
ripple is not so deep that the regulator has nothing ot discard at the
minimum points on the ripple.
What is the secondary voltage from the transformer you are using to
drive the 30 volt 4 amp linear regulator?