Maker Pro
Maker Pro

Question about Modelling the ESR of a Capacitor

K

K2

Jan 1, 1970
0
Hi Guys,

under:

http://www.avxcorp.com/docs/techinfo/eqtant.pdf

you can find some basics about the 'ESR' of a Capacitor.

A formula is shown describing the 'ESR' as: Rp/((2*Pi*f*Cp*Rp)^2+1)
and the 'ESC' is : Cp+1/((2*Pi*f*Rp)^2*Cp)



I guess, that the basic model looks like this:

|| __________ __________
--------o----------||--------o-----|__________|-------|==========|----
| || Cp | Rs Ls
| ___________ |
|---|___________|----|
Rp


My first Questions:

Is the formula for the ESR correct??
Paralleling Cp and Rp should result into an impedance of:
Rp/sqrt(1+(2*Pi*f*R*C)^2)

Or NOT????


My second Question:

I don't have a glue how the 'ESC' has to be calculated at all.
What is the idea behind that?



So long


Karsten
 
J

John Larkin

Jan 1, 1970
0
Hi Guys,

under:

http://www.avxcorp.com/docs/techinfo/eqtant.pdf

you can find some basics about the 'ESR' of a Capacitor.

A formula is shown describing the 'ESR' as: Rp/((2*Pi*f*Cp*Rp)^2+1)
and the 'ESC' is : Cp+1/((2*Pi*f*Rp)^2*Cp)



I guess, that the basic model looks like this:

|| __________ __________
--------o----------||--------o-----|__________|-------|==========|----
| || Cp | Rs Ls
| ___________ |
|---|___________|----|
Rp


My first Questions:

Is the formula for the ESR correct??
Paralleling Cp and Rp should result into an impedance of:
Rp/sqrt(1+(2*Pi*f*R*C)^2)

Or NOT????


My second Question:

I don't have a glue how the 'ESC' has to be calculated at all.
What is the idea behind that?



So long


Karsten

ESR = Rs.

I have no idea what ESC stands for.

Avoid tantalums. They tend to explode.

John
 
P

Phil Allison

Jan 1, 1970
0
"K2"
http://www.avxcorp.com/docs/techinfo/eqtant.pdf

you can find some basics about the 'ESR' of a Capacitor.

A formula is shown describing the 'ESR' as: Rp/((2*Pi*f*Cp*Rp)^2+1)
and the 'ESC' is : Cp+1/((2*Pi*f*Rp)^2*Cp)


** The formulae applies to fig 4 which shows a perfect capacitor in
parallel with a resistor.


I guess, that the basic model looks like this:

|| __________ __________
--------o----------||--------o-----|__________|-------|==========|----
| || Cp | Rs Ls
| ___________ |
|---|___________|----|
Rp



** No.

Fig 4 does not show what you drew.


My first Questions:

Is the formula for the ESR correct??


** For the case shown in of fig 4 only.


My second Question:

I don't have a glue how the 'ESC' has to be calculated at all.
What is the idea behind that?


** To make the parallel and serie scircuits bahave the same at the frequency
of interest.

Same impedance and same phase angle.




........ Phil
 
J

Jean-Yves

Jan 1, 1970
0
K2 said:
Hi Guys,

under:

http://www.avxcorp.com/docs/techinfo/eqtant.pdf

you can find some basics about the 'ESR' of a Capacitor.

A formula is shown describing the 'ESR' as: Rp/((2*Pi*f*Cp*Rp)^2+1)
and the 'ESC' is : Cp+1/((2*Pi*f*Rp)^2*Cp)



I guess, that the basic model looks like this:

|| __________ __________
--------o----------||--------o-----|__________|-------|==========|----
| || Cp | Rs Ls
| ___________ |
|---|___________|----|
Rp


My first Questions:

Is the formula for the ESR correct??
Paralleling Cp and Rp should result into an impedance of:
Rp/sqrt(1+(2*Pi*f*R*C)^2)

Or NOT????


My second Question:

I don't have a glue how the 'ESC' has to be calculated at all.
What is the idea behind that?



So long


Karsten

some beginning of the answer... :
http://members.ozemail.com.au/~bobpar/k7214.pdf

regards,
 
Top