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Remedy: upload a circuit diagram of how your resistors are connected using the 'image' button #15 from the left in the text entry's menu bar.Since we can't see your circuit we can't tell.
Since we can't see your circuit we can't tell.
A simple general solution is to find a pair of resistors either in series or parallel and replace then with a single resistance of the calculated combined value. Repeat this process until there is only one resistor left.
There are circuit topologies of resistors (I think the simplest has 5 resistors) where this process can't be used to completely solve it, but as I can't see your circuit...
Remedy: upload a circuit diagram of how your resistors are connected using the 'image' button #15 from the left in the text entry's menu bar.
steve  in this forum is it ok to suggest a theorem by name without giving away the details?
Kirchhoff, Superposition Theorem, Series/Parallel, Current Divider, Voltage Divider and System equationsThat circuit can't be simplified using simple formulae for resistors in series and parallel.
You need to employ another type of circuit analysis.
What other methods do you know?
I tried to use a System of equations using the Kirchhoffs Laws but nothingCan you apply KVL and KCL to this circuit? Did you learn to use this to determine all voltages and currents in a circuit?
Try again. That is the way to do it. Find currents and voltages in the circuit, then use the current through the voltage source to find the equivalent resistance using Ohm's law.I tried to use a System of equations using the Kirchhoffs Laws but nothing
I tried to use a System of equations using the Kirchhoffs Laws but nothing