Hi Muhammad
the figures might be correct but the units are not - your usage is measured in watt-hours. Just as you have found, Energy = Power x Time.
You now know that you must supply 2144 watt hours of energy every day, which is the same as 2.144 kWh (kilowatt hours).
Now in order to be sure you can supply that energy you need to consider your worst likely day and design for it. Perhaps you can place your panels in a position where they'll receive 4 hours of sunlight on the worst day you plan for. If so, you will need 500 watts of panels.
There is more expensive news unfortunately - you need to supply an overhead for losses. All systems are inefficient, and since you are going to store energy in your batteries the losses of the batteries must be supplied. At a guess you'd want at least an extra 20% of generating capacity.
So that's 2572.8 watt hours every day... ridiculous precision but I gave you the exact arithmetic so that you can be sure you appreciate the method. We never round such figures down... lets call that 2600Wh or 2.6kWh usage per day including losses at 20%.
I am not sure that I have made enough allowance for losses here, by the way. I very much fear that 40% may be more realistic by the time power conversion losses in your inverter are considered.
Isn't this awfully expensive? You bet it is. Are there ways to economise? Thankfully, yes. But not enough to make the job as cheap as you'd like.
Economies are achieved by using the power at the voltage it is supplied by the batteries, by using thick cable (bigger installation cost but saves generating capacity), and by using lower powered appliances.
These 2 x 14W "savers"' for instance. Are they lighting? Try replacing them with single led's which run straight off the 12V and are installed right where you want the light. Don't try and light the whole room. That will save heaps of pwer, and you'll be able to plan a smaller installation.
There's doubtless lots to say yet but this'll give you plenty to chew on for a day or 2, I guess.