Below is my LTspice simulation:
The current (yellow trace) starts at zero since current can't instantly start in a inductor (you have to use the uic option in the transient simulation).
It then rises to the resonant peak (here about 7.3A simulated) where the capacitance voltage (green trace) is zero and all the capacitor energy has been transferred to the inductor current (minus any resistive losses).
Since this is a lossy resonant circuit it will continue to have a decaying oscillation, with the energy being transferred back and forth between the capacitor voltage and the inductor current (note the 90° phase difference between voltage and current), until all the energy is dissipated in the circuit parasitic resistances.
If you don't want the circuit to oscillate (and also prevent the capacitor voltage from going negative which can damage an electrolytic), you can put a high-voltage diode in parallel with the capacitor (cathode to positive).
That will allow the inductor current to reach the maximum current (red trace) and then decay to zero as determined by the resistive and diode losses from the current.
An easy way to determine the peak current (ignoring the resistances) is to calculate at what current the inductor energy equals the original capacitor energy (1/2 CV² = 1/2 LI²).
That gives a value of 7.9A for this circuit.