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Thermocouple

D

Danny

Jan 1, 1970
0
Hi

I am making a thermocouple from Copper/Constantan, i plan to twist the
ends together at the appropriate junctions, and then solder them in
place, a spot welder is a little bit out of my league, would the solder
affect the performance of the thermocouple or not?


Danny
 
J

John Woodgate

Jan 1, 1970
0
I read in sci.electronics.design that Danny <[email protected]>
wrote (in said:
I am making a thermocouple from Copper/Constantan, i plan to twist the
ends together at the appropriate junctions, and then solder them in
place, a spot welder is a little bit out of my league, would the solder
affect the performance of the thermocouple or not?

Provided it doesn't melt, no. The thermal voltage is not developed at
the junctions, contrary to popular belief, but in the wires themselves.
Even though you may have two junctions, copper-solder and solder-
constantan, they are both at the same temperature, so there is no
spurious voltage.
 
J

James Meyer

Jan 1, 1970
0
I read in sci.electronics.design that Danny <[email protected]>


Provided it doesn't melt, no. The thermal voltage is not developed at
the junctions, contrary to popular belief, but in the wires themselves.
Even though you may have two junctions, copper-solder and solder-
constantan, they are both at the same temperature, so there is no
spurious voltage.

This is 100% in line with my research into thermocouples.

Jim
 
J

JeffM

Jan 1, 1970
0
Even though you may have two junctions,
copper-solder and solder-constantan,
they are both at the same temperature, so there is no spurious voltage.
John Woodgate

This assumes that the copper-solder junction
produces a voltage which is equal and opposite
to that of the solder-constantan junction
(facts not in evidence).
 
J

John Woodgate

Jan 1, 1970
0
<[email protected]>) about 'Thermocouple',
This assumes that the copper-solder junction
produces a voltage which is equal and opposite
to that of the solder-constantan junction
(facts not in evidence).

The junctions DO NOT produce any voltages, contrary to popular belief.
Thermoelectric voltages are produced by the temperature gradients in the
wires.
 
S

Spehro Pefhany

Jan 1, 1970
0
This assumes that the copper-solder junction
produces a voltage which is equal and opposite
to that of the solder-constantan junction
(facts not in evidence).

If there is no temperature difference, then there is no voltage.
Always.

Best regards,
Spehro Pefhany
 
J

John Popelish

Jan 1, 1970
0
JeffM said:
This assumes that the copper-solder junction
produces a voltage which is equal and opposite
to that of the solder-constantan junction
(facts not in evidence).

Junctions do not produce voltage. Changes in temperature along
conductors is what produces thermocouple voltage. As long as the
solder joint is small enough to be at essentially one temperature, it
produces no error voltage.
 
J

James Meyer

Jan 1, 1970
0
This assumes that the copper-solder junction
produces a voltage which is equal and opposite
to that of the solder-constantan junction
(facts not in evidence).

The facts that *are* in evidence state that the voltage generated by a
thermocouple is *not* generated at the junctions. The voltage is generated
along the length of the conductors due to the temperature differences between
the ends of the conductors.

In point of fact, a junction is not required at all for the generation
of a voltage. A conductor with a temperature difference between its ends will
generate a voltage. No junction is required unless you want to make use of a
current flow due to the voltage generated.

A little research before you post will reduce the number of times you
put your foot in your mouth.

Jim
 
L

Luhan Monat

Jan 1, 1970
0
John said:
The junctions DO NOT produce any voltages, contrary to popular belief.
Thermoelectric voltages are produced by the temperature gradients in the
wires.

Wow, this is not what I learned in my university physics class! It all
had to do with how the free electrons interacted at the junction. Also,
I have never heard of voltage created by temperature gradients.

Do you have some acedemic reference your position? I would like to
check this out and settle the matter for myself.
 
S

Spehro Pefhany

Jan 1, 1970
0
Wow, this is not what I learned in my university physics class! It all
had to do with how the free electrons interacted at the junction. Also,
I have never heard of voltage created by temperature gradients.

No, it's the free electrons in the wires, which have a temperature
gradient along them. The distribution of the gradient in a homogenous
wire is not particularly important (law of Magnus). A T/C measures the
difference between those potentials in different metals.

An ideal T/C would have a zero-width junction. Obviously no
temperature delta across that with finite heat flow. Real T/Cs have
almost no delta-T across or even near the alloyed region that is the
junction.
Do you have some acedemic reference your position? I would like to
check this out and settle the matter for myself.

Look up Seebeck (coefficient), as well as Peltier and Thomson (that
Lord Kelvin bloke).

Best regards,
Spehro Pefhany
 
J

John Woodgate

Jan 1, 1970
0
I read in sci.electronics.design that Luhan Monat
Wow, this is not what I learned in my university physics class! It all
had to do with how the free electrons interacted at the junction. Also,
I have never heard of voltage created by temperature gradients.

Do you have some acedemic reference your position? I would like to
check this out and settle the matter for myself.

No, I don't have any references; I don't have access to a university
library. But I feel sure you will find the information on the Net with a
Google search, with appropriate references.
 
J

John Popelish

Jan 1, 1970
0
Luhan said:
Yep, its the gradient in each wire plus a small contribution from the
junction itself.

Do you have a name for the effect that causes this small gradient at
the junction, so I could look it up?

I have never heard of such a thing. I have used intrinsic junctions
made by welding the two thermocouple wires to some third metal object,
to measure the approximate average of temperature between the two
contact points. The composition of the metal between the two
thermocouple leads appears to have no effect on the temperature
reading.
 
L

Luhan Monat

Jan 1, 1970
0
Yep, its the gradient in each wire plus a small contribution from the
junction itself.
 
J

John Popelish

Jan 1, 1970
0
Luhan said:
Yep, its the gradient in each wire plus a small contribution from the
junction itself.

Here is an introduction to thermoelectricity:
http://www.chem.cornell.edu/fjd3/thermo/intro.html

I see no mention of a voltage at the junction of two dissimilar
materials.

Besides, if such a junction could produce a voltage (that could create
a continuous current) at a single temperature, it would violate the
conservation of energy. It would produce continuous power with no
absorption of energy from anywhere.
 
C

Charles DH Williams

Jan 1, 1970
0
John Popelish said:
Do you have a name for the effect that causes this small gradient at
the junction, so I could look it up?

There is a so-called 'contact-potential' which is a contribution to
the electrochemical potential but other contributions (from a charge
double-layer at the boundary) cancel it out so there is no net
electrochemical potential difference across a metal-metal
junction at equilibrium.

Strictly speaking, a normal voltmeter measures electrochemical
potential difference, not electrostatic potential difference.

Charles.
 
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