# Three phase induction generator on a single phase supply

#### dec335

Oct 9, 2010
2
Hi,
I’m really stuck on a problem for my final year project in my taught Masters degree and any suggestions what might be going wrong would be greatly appreciated.
I’m trying to run a three phase delta connected induction generator on a single phase supply using a Steinmetz connection. The Steinmetz connection is a single capacitor connected across phase B or C depending on which direction the machine is running with phase A connected to the single phase supply. I’ve been using the book Distributed Generation by Chan and Lai to get the formulas shown below. It says in the book for a balanced machine the following applies.

Yp = 1/Zp =|Yp|∠-ϕp
Where Yp is the positive sequence admittance of the generator and ϕp is the positive sequence impedance angle.

B1 = 2Yp sin⁡(2π/3 – ϕp)
B2 = 2Yp sin⁡(ϕp - π/3)
B = 1/Xc
C1 = B1/(2.π.f)
C2 = B2/(2.π.f)

I ran the machine as an induction motor first and a certain calculated speed it had an impedance of Z = 124.26∠60 (62.2 + j107.6) and this gave a value of Yp as 0.0085∠-60, B1 = 0 and B2 = -0.0139388. A modular value of B2 was used to calculate a positive capacitance value and this was calculated as 0.00004439 which is equivalent to 44μF. This capacitance was placed on the motor across phase B and it worked really well. It was able to run with a load and all the phases were in balance with the voltages and currents very close together. (The figures have been rounded up for these examples as I have been using an excel sheet that has much longer values in each cell)

I tried to run the machine as an induction generator and a certain calculated speed it had an impedance of Z = 104.41∠120 (-52.26 + j90.4)(the real value is negative as it has a negative slip) and this gave a value of Yp as 0.00958∠-120, B1 = -0.016588 and B2 =0. A modular value of B1 was used to calculate a positive capacitance value and this was calculated as 0.00005282 which is equivalent to 52μF. This capacitance was placed on the machine across phase B and it wouldn’t work properly. There was a lot of imbalance in the currents and voltages.
Would anyone have any idea of why it is not working for the induction generator the same as for the induction motor as all the literature I have read has said that an induction generator behaves exactly the same as an induction motor but it is just run faster? I have been doing tests by trial and error but I have to give a reason why it is not working. If any more information is required, just post a question and I will answer it.
Thanks
Declan

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#### Militoy

Aug 24, 2010
180
You don't specifically mention that you drove the shaft faster than the rotating flux (The natural synchronous speed of the equivelant induction motor). The induction generator isn't intended to behave exactly the same as an induction motor, but faster - it's intended to produce power when excited, and the shaft is mechanically driven at a higher than synchronous speed. Perhaps I missed something in your description of the problem - can you describe the way you are driving the shaft?

Last edited:

#### dec335

Oct 9, 2010
2
Militoy,
The shaft is being driven faster than synchronous speed by a dc motor in the lab.
Declan

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