I wonder if anyone can work out an equation that describes the voltage seen on the input of a DC-DC boost converter when the output of the converter is providing current at a regulated/fixed voltage and the voltage source has an internal resistance that is not negligible.
This is important when you consider a small 1.5V battery having its voltage boosted up and driving a load (to, say, 2.5V). The battery has a few 100milliOhm resistance. When a load is put on the converter, the battery supplies current. That current produces a voltage drop across the internal resistance of the battery, and so the voltage at the converter drops.
Because there is less voltage, more current is required to maintain the power, so more current is drawn and the voltage drops further.
Basically, after a point, the battery voltage collapses rapidly and disproportionaly to the increase in load.
Its doing my head in trying to work out an equation for this relationship. Anyone able to help me out here?
Observed voltage on Battery = func of (Vbatt, Rbat, Iload, Vload)
This is important when you consider a small 1.5V battery having its voltage boosted up and driving a load (to, say, 2.5V). The battery has a few 100milliOhm resistance. When a load is put on the converter, the battery supplies current. That current produces a voltage drop across the internal resistance of the battery, and so the voltage at the converter drops.
Because there is less voltage, more current is required to maintain the power, so more current is drawn and the voltage drops further.
Basically, after a point, the battery voltage collapses rapidly and disproportionaly to the increase in load.
Its doing my head in trying to work out an equation for this relationship. Anyone able to help me out here?
Observed voltage on Battery = func of (Vbatt, Rbat, Iload, Vload)