A voltage divider circuit is to be constructed to obtain an output voltage 3 V (ptp) from an a.c. supply of 12 V (ptp). If the value of one of the available resistor pair is 6 kΩ, then what is the value of the other resistor with the output voltage across it is?
I would the 3v Be V2 in an equation where V1 would be 9 since the overal voltage going through is 12v? if so then i remember learning somewhere that V1/V2 = R1/R2.
i get the answer of 2kΩ only when i do: (v2)3/(v1)9= 0.33333333333 x 6kΩ= 2kΩ
so R2= 2kΩ BUT i wont get that if i did v1(9)/v2(3)=3??
I would the 3v Be V2 in an equation where V1 would be 9 since the overal voltage going through is 12v? if so then i remember learning somewhere that V1/V2 = R1/R2.
i get the answer of 2kΩ only when i do: (v2)3/(v1)9= 0.33333333333 x 6kΩ= 2kΩ
so R2= 2kΩ BUT i wont get that if i did v1(9)/v2(3)=3??