Maker Pro
Maker Pro

What's the total resistance of this network?

R

Robert Baer

Jan 1, 1970
0
David said:
If you are lucky enough to have A=E and C=D then B=0 ohms, in which
case it's super easy ;-)

Dave :)
Equality is not a necessary condition for a balanced bridge.
 
F

Fred Bloggs

Jan 1, 1970
0
Robert said:
Equality is not a necessary condition for a balanced bridge.

And how some moron can conclude that B must be zero is beyond me. The
David L. Jones sounds a lot like that fag Grise in many ways with the
trivial non-informational content of his posts and the inclusion of the
smiley, which is quite sickening when you think of the marijuana stained
brown teeth....
 
D

David L. Jones

Jan 1, 1970
0
And how some moron can conclude that B must be zero is beyond me. The
David L. Jones sounds a lot like that fag Grise in many ways with the
trivial non-informational content of his posts and the inclusion of the
smiley, which is quite sickening when you think of the marijuana stained
brown teeth....


You are all class "Fred"

In case you can't figure it out on your own and you really want to
know... a common (and often taught) way to solve these resistor
problems is by finding equipotential nodes, and once found, the
technique is to short those nodes together, thus reducing the
complexity of the circuit and making it easier to analyse.

So in this case, if it happened that A=E and C=D, then the two inner
nodes are obviously equipotential so you could short them out, thus
giving B=0 using this technique.

I was not implying that B *must* be 0, in fact, if A=E and C=D then B
can be infinite as well.

Dave :)
 
Top