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It doesn't, unless the load always remains the same.Hello,
Why does the current always remain the same in a series circuit?
We have voltage drop in each resistor,
for example in resistor one with 20 ohm resistance we have 200V Voltage, so I=V/R ==> 200 / 20 = 10A .
We assume a bit voltage drop in resistor two and voltage is 195 V , So I = V/R ==> 190/20 = 9.5 A
Now we don't have the same current in series circuit
Hello,
Why does the current always remain the same in a series circuit?
We have voltage drop in each resistor,
for example in resistor one with 20 ohm resistance we have 200V Voltage, so I=V/R ==> 200 / 20 = 10A .
We assume a bit voltage drop in resistor two and voltage is 195 V , So I = V/R ==> 190/20 = 9.5 A
Now we don't have the same current in series circuit
Hello,
Why does the current always remain the same in a series circuit?