hey again,.....

ive attached the question and heres my working, can anyone tell me if im on the right lines?

i then know zener voltage is equal to load voltage

which means the voltage through Rs =

(20 - 14.2)

= 5.8V

i then said that if the maximim current through the zener is 60ma then there will be no current through RL so Rs must be equal to 5.8 / 0.06 = 96.66 ohms? i dunno its a wild guess tbh.

actually thats wrong because

load current + zener current flows through Rs

i think knee current is the amount the zener can handle when the voltage is reversed, not to sure on this tho n if it is how does this help in any way?

thanks again.

ive attached the question and heres my working, can anyone tell me if im on the right lines?

i then know zener voltage is equal to load voltage

which means the voltage through Rs =

(20 - 14.2)

= 5.8V

i then said that if the maximim current through the zener is 60ma then there will be no current through RL so Rs must be equal to 5.8 / 0.06 = 96.66 ohms? i dunno its a wild guess tbh.

actually thats wrong because

load current + zener current flows through Rs

i think knee current is the amount the zener can handle when the voltage is reversed, not to sure on this tho n if it is how does this help in any way?

thanks again.