hey again,.....
ive attached the question and heres my working, can anyone tell me if im on the right lines?
i then know zener voltage is equal to load voltage
which means the voltage through Rs =
(20 - 14.2)
= 5.8V
i then said that if the maximim current through the zener is 60ma then there will be no current through RL so Rs must be equal to 5.8 / 0.06 = 96.66 ohms? i dunno its a wild guess tbh.
actually thats wrong because
load current + zener current flows through Rs
i think knee current is the amount the zener can handle when the voltage is reversed, not to sure on this tho n if it is how does this help in any way?
thanks again.
ive attached the question and heres my working, can anyone tell me if im on the right lines?
i then know zener voltage is equal to load voltage
which means the voltage through Rs =
(20 - 14.2)
= 5.8V
i then said that if the maximim current through the zener is 60ma then there will be no current through RL so Rs must be equal to 5.8 / 0.06 = 96.66 ohms? i dunno its a wild guess tbh.
actually thats wrong because
load current + zener current flows through Rs
i think knee current is the amount the zener can handle when the voltage is reversed, not to sure on this tho n if it is how does this help in any way?
thanks again.